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2 years ago

Round 5049 correct to 1 significant figure

Mathematics

2 answers:

Step2247 [10]2 years ago

7 0

5000

Addition (+) and subtraction (-) round by the least number of decimals.
Multiplication (* or ×) and division (/ or ÷) round by the least number of significant figures.
Logarithm (log, ln) uses the input's number of significant figures as the result's number of decimals.
Antilogarithm (n^x.y) uses the power's number of decimals (mantissa) as the result's number of significant figures.
Exponentiation (n^x) only rounds by the significant figures in the base.
To count trailing zeros, add a decimal point at the end (e.g. 1000.) or use scientific notation (e.g. 1.000 × 10^3 or 1.000e3).
Zeros have all their digits counted as significant (e.g. 0 = 1, 0.00 = 3).
Rounds when required, after parentheses, and on the final step.

- BRAINLIEST answerer ❤️

Bogdan [553]2 years ago

7 0

Answer:

5000

hope this helps you :)

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3 years ago

At a price of $9 per box of oranges, the supply is 320,000 boxes and at a price of $8.50 per box, the supply is 270,000 boxes. F

artcher [175]

We want to find a linear equation that models the given situation.

The solution is p = $0.0001*q - $23

The general linear equation is:

p = m*q + c

Where m is the slope and c is the y-intercept.

If we know that the line passes through two points (x₁, y₁) and (x₂, y₂) then the slope can be written as:

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Here we have the two points:

price = $9, boxes = 320,000

price = $8.50, boxes = 270,000

We can rewrite these as:

(320,000 , $9)

(270,000 , $8.50)

Then the slope of the line will be:

$m = \frac{\$ 9 - \$ 8.50}{320,000 - 270,000} = \$ 0.00001$

Then the line is something like:

p = $0.0001*q + c

To find the value of c we can use one of the two given points, I will use the first one, (320,000 , $9).

Replacing that in our equation we get:

$9 = $0.0001*320,000 + c

$9 - $0.0001*320,000 = c = -$23

Then the linear equation is:

p = $0.0001*q - $23

If you want to learn more you can read:

brainly.com/question/11687874

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2 years ago

In a given year, the average annual salary of a NFL football player was $189,000 with a standard deviation of $20,500. If a samp

nika2105 [10]

Answer:

15.15% probability that the sample mean will be $192,000 or more.

Step-by-step explanation:

To solve this problem, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central Limit Theorem

The Central Limit Theorem estabilishes that, for a random variable X, with mean $\mu$ and standard deviation $\sigma$ , a large sample size can be approximated to a normal distribution with mean $\mu$ and standard deviation $s = \frac{\sigma}{\sqrt{n}}$