Answer:
Explanation:
The change in enthalpy of a substance when heated is given by
ΔH = m x Csp x ΔT
so the enthalpy change is dependent on the specific heat , i.e its capactity to absorb heat, and is not influenced by factors such as being closer to the melting point, volume , potential energy or being a solid or liquid.
Answer:
Electrones de valencia.
Explanation:
¡Hola!
En este caso, dado en química se conocen las estructuras de Lewis como representaciones gráficas de como los elementos están enlazados entre sí, debemos tener en cuenta que estos enlaces se forman entre los electrones de valenciam, los cuales son utilizados para su representación. Se sabe que los electrones de valencia son representados con puntos alrededor del elemento a través de puntos que se unen entre sí y son el número de electrons en la capa más externa de los elementos en cuestión; por ejemplo, cloro tiene 7 electrones de valencia, azufre tiene 6, hidrogeno 1, carbono 4 y así sucesivamente.
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Answer:
please I think the answer is A.
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and sorry if it doesn't help.
Answer:
<u>One lone-Pair is present in Ammonia</u>
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Explanation:
The number of valence electron in N = 5
The number of Valence electron in H = 1
The formula of ammonia = NH3
Total valence electron in ammonia molecule = 5 +3(1) = 5+3 = 8
The lewis structure suggest that :
Nitrogen completes its octet by sharing the electron pair with 3 hydrogen atoms.
3 electron of Nitrogen are involved in sharing with Hydrogen
So,<u><em> remaining two electron are left non-bonded</em></u> . Hence they exist as lone- pair
So, there is only 1 lone pair in the ammonia molecule .
The shape of NH3 is bent according to VSEPR theory . This is so because the presence of 1 lone pair causes more repulsion and occupy more space.
Thus the lone pair is changing the shape of the ammonia molecule . It also increase the dipole moment of the molecule , which gives polarity to it.
Answer:
Atomic number of this isotope = 77
Explanation:
Given that,
Mass number = 193
No of neutrons = 116
We need to find the atomic no of this isotope.
We know that,
Atomic mass = No of protons + No. of neutrons
Also, atomic no = no of protons
So,
Atomic mass = atomic no + No. of neutrons
⇒ Atomic no = Atomic mass - no of neutrons
Atomic no = 193 - 116
Atomic no = 77
Hence, 77 is the atomic no of the isotope.