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professor190 [17]
3 years ago
8

Use the standard reaction enthalpies given below to determine ΔH°rxn for the following reaction: 4 SO3(g) → 4 S(s) + 6 O2(g) ΔH°

rxn = ? Given: SO2(g) → S(s) + O2(g) ΔH°rxn = +296.8 kJ 2 SO2(g) + O2(g) → 2 SO3(g) ΔH°rxn = -197.8 kJ
Chemistry
1 answer:
siniylev [52]3 years ago
8 0

Answer:

Explanation:

We are going to manipulate the equations:

    SO2(g) → S(s) + O2(g) ΔH°rxn = +296.8

 2 SO2(g) + O2(g) → 2 SO3(g) ΔH°rxn = -197.8 kJ

So that after we add them together we will get the desired equation:

4 SO3(g) → 4 S(s) + 6 O2(g) ΔH°rxn = ?

The  ΔH°rxn  will then be added according to Hess´s law to get our answer.

Notice that S has a coefficient of 4, and it only appears in the first as 1 mole. Therefore we will multiply  it by 4. Also, notice in the final equation we want the sulfur as product, so we need to multiply by 4 the first equation:

    4 SO2(g) → 4 S(s) + 4 O2(g)      ΔH°rxn =( +296.8 kJ  ) x 4 = 1,187.20 kJ

Working with the second equation, we can see that if we multiply this equation by 2 and reverse it, when we add it  to the previously manipulated equation, we can cancel the SO2s which are not present in our desired reaction:

4 SO3(g)   → 4  SO2(g) +  4 O2(g)  ΔH°rxn = ( + 197.8 kJ) x 2   = 395.6 kK

adding our worked equations:

    4 SO2(g) →   4 S(s) +          4 O2(g)               ΔH°rxn = 1187.2 kJ

    4 SO3(g)   → 4  SO2(g) +  2 O2(g)                ΔH°rxn =  395.6 kJ

____________________________________________________

4 SO3(g)  →   4 S(s)  + 6  O2(g)                        ΔH°rxn =  1582.8 kJ

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vodka [1.7K]

Table Giving Answer

Element Atomic mass % Amount

Mg_24     24                79    18.96

Mg_25 25                10    2.5

Mg_26 26                11   2.86

   

Total                     24.32

Discussion

The method of calculation for this table, which was done in Excel (a spread sheet) is shown below. Assume that there is 100 grams of material of "pure" magnesium. What is it's mass?

<em><u>Sample  Calculation</u></em>

The the sample atomic mass = 24

Mass = % * sample atomic mass

Mass = 79% * 24

Mass = (79/100) * 24

Mass = 18.96

<em><u>Note</u></em>

The other two elements are found exactly the same as the sample calculation.

Then all you do is add the 3 masses together.

Answer

The mass of Mg to 1 decimal place is 24.3 <<<< Answer.


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