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2 years ago

What is the equation of a line perpendicularto y=-2/5x-1 that passes through(2,-8)

Mathematics

1 answer:

Andrews [41]2 years ago

7 0

<h2>Answer: y = ⁵/₂ x - 13 OR y + 8 = ⁵/₂ x - 5 </h2>

<h3>Step-by-step explanation:</h3>

<u>Find the slope of the perpendicular line</u>

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are <em>negative-reciprocal</em>s of each other.

⇒ if the slope of this line = - ²/₅

then the slope of the perpendicular line (m) = ⁵/₂

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

⇒ y - (-8) = ⁵/₂ (x - 2)

∴ y + 8 = ⁵/₂ (x - 2)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

since y + 8 = ⁵/₂ (x - 2)

y = ⁵/₂ x - 13

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Answer:

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Now let us find z-score for 86.

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Now we will find P(-1<Z) which is probability that a random score would be greater than 68. We will find P(2>Z) which is probability that a random score would be less than 86.

Using normal distribution table we will get,

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We will use formula $P(a$ to find the probability to find that a normal variable lies between two values.

Upon substituting our given values in above formula we will get,

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2 years ago

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Recall your d = rt, distance = rate * time

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&distance&rate&time(hrs)\\
&-----&-----&-----\\
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\end{array}\\\\
-----------------------------\\\\

\begin{cases}
\boxed{d}=(55)(x)\\\\
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Hunter-Best [27]

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What is the equation of a line perpendicularto y=-2/5x-1 that passes through(2,-8)​

What is the equation of a line perpendicularto y=-2/5x-1 that passes through(2,-8)