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taurus [48]
2 years ago
13

What is the equation of a line perpendicularto y=-2/5x-1 that passes through(2,-8)​

Mathematics
1 answer:
Andrews [41]2 years ago
7 0
<h2>Answer: y =  ⁵/₂ x - 13   OR  y + 8 =  ⁵/₂ x - 5 </h2>

<h3>Step-by-step explanation:</h3>

<u>Find the slope of the perpendicular line</u>

When two lines are perpendicular, the product of their slopes is -1. This means that the slopes are <em>negative-reciprocal</em>s of each other.

⇒  if the slope of this line = - ²/₅

      then the slope of the perpendicular line (m) = ⁵/₂

<u>Determine the equation</u>

We can now use the point-slope form (y - y₁) = m(x - x₁)) to write the equation for this line:

                                ⇒  y - (-8) =  ⁵/₂ (x - 2)

                                   ∴  y + 8 = ⁵/₂ (x - 2)

We can also write the equation in the slope-intercept form by making y the subject of the equation and expanding the bracket to simplify:

                  since   y + 8 =  ⁵/₂ (x - 2)

                                    y =  ⁵/₂ x - 13

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