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sergey [27]
3 years ago
6

How do you determine whether to use 22/7 or 3.14 for π ?

Mathematics
1 answer:
Korolek [52]3 years ago
6 0

Answer:

  Use the value the problem statement tells you. Otherwise, use a better approximation.

Step-by-step explanation:

π ≈ 3.141592653589793238... (a non-repeating infinite decimal)

3.14 = 3.14

22/7 = 3.142857142857_142857

355/113 = 3.14159292035... (a very long repeating decimal)

You can see that the third decimal place is wrong in both of your approximations. The last approximation shown has 7 good decimal digits. A good scientific or graphing calculator will have an internal value for pi that is good to 10 or 12 digits or more (preferably, at least 32 digits).

You should use a value for pi that has at least one more digit of accuracy than the number of significant digits in your answer.

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Complete Question:

Johnny printed two maps of a walking trail near his home. The length of the walking trail on the first map is 8 cm.

(a) Choose a length between 5 cm and 15 cm for the walking trail on the second map: ________cm.  

(b) Determine the scale factor from the first map to the second map.

(c)  A landmark on the first map is a triangle with side lengths of 3 cm, 4 cm, and 5 cm. What are the side lengths of the triangle landmark on the second map?  

(d) Draw one of the triangles from part C. Label the side lengths and vertices accordingly. You may use this drawing tool or draw your triangle on paper:

Answer:

(a) Length = 4cm

(b) Scale factor = 0.5

(c) 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

Step-by-step explanation:

(a) Choose a length between 5 cm and 15 cm

Length =4cm <em>--- This is solely up to you (you can make use of any length between 5 cm and 15 cm)</em>

(b) The scale factor

The scale factor (k) is calculated as:

k = \frac{New\ Length}{Old\ Length}

k = \frac{4cm}{8cm}\\

k = 0.5

(c) What are side lengths of 3 cm, 4 cm, and 5 cm on the second landmark

Using:

k = \frac{New\ Length}{Old\ Length}

The old lengths, in this case are: 3cm, 4cm and 5cm

Make New length the subject

New\ Length = k * Old\ Length

When Length = 3cm

New\ Length = 0.5 * 3cm = 1.5cm

When Length = 4cm

New\ Length = 0.5 * 4cm = 2cm

When Length = 5cm

New\ Length = 0.5 * 5cm = 2.5cm

So: 3cm, 4cm and 5cm are represented by 1.5cm, 2cm and 2.5cm respectively, on the second scale

(d) See attachment for triangle

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