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Nina [5.8K]
2 years ago
9

What would be the mass of 4.56x10²³ water molecules

Chemistry
1 answer:
kifflom [539]2 years ago
3 0
Every time you see molecules, atoms, & particles think of avagadros #. (6.022 x 10^23)

Answer: 13.6 grams of H2O

Solution: (4.56x10^23) x (1 mol H2O/6.022x10^23) x (18 grams H2O/1 mol H2O) = 13.6 grams of H2O

Using dimensional analysis above makes these types of problems easy.
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Assuming 1 mol of Fe3+ and 2 mol of SCN- were allowed to react and reach equilibrium. 0.5 mol of product was formed. The total v
zaharov [31]

Answer:

a. 0.5 mol

b. 1.5 mol

c. 0.67

Explanation:

Fe3+ + SCN- -----> [FeSCN]2+

a. The ratio of the product to Fe3+ is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of Fe3+ was used. Leaving 0.5 mol remaining at equilibrium

b. The ratio of the product to SCN= is 1:1. Meaning that if 0.5 mol of product was produced up then 0.5 mol of SCN- was used. Leaving 1.5 mol remaining at equilibrium

c. KC =  0.5/(0.5*1.5) =  0.67

3 0
3 years ago
What is the advantage of having valves in the
fenix001 [56]
The valves stop the blood from flowing backwards
6 0
3 years ago
Question 5 of 10
djyliett [7]

A. A diagram showing the effects of temperature and pressure on  phase

Explanation:

A phase diagram is a diagram that shows the effects of temperature and pressure on phase.

  • A phase diagram shows how different substances are transformed from one form to another.
  • The transformation is an interplay between pressure and temperature.
  • The phase graph represents physical state changes.
  • A phase change is made up of pressure on the y-axis and temperature on the x - axis.

Learn more:

Phase change brainly.com/question/1875234

#learnwithBrainly

4 0
3 years ago
Argon (Ar) and helium (He) are initially in separate compartments of a container at 25°C. The
love history [14]

Answer:

(a) V_B=11.68L

(b) x_{He}=0.533

Explanation:

Hello,

In this case, since the both gases behave ideally, with the given information we can compute the moles of He in A:

n_A=\frac{0.082\frac{atm*L}{mol*K}*298K}{1.974 atm*6.00L}=2.063mol

Thus, since the final pressure is 3.60 bar, we can write:

P=x_{Ar}P_A+x_{He}P_B\\\\P=\frac{n_{Ar}}{n_{Ar}+n_{He}} P_A+\frac{n_{He}}{n_{Ar}+n_{He}} P_B\\\\3.60bar=\frac{2.063mol}{2.063mol+n_{He}} *2.00bar+\frac{n_{He}}{2.063mol+n_{He}} *5.00bar

The moles of helium could be computed via solver as:

n_{He}=2.358mol

Or algebraically:

3.60bar=\frac{1}{2.063mol+n_{He}} *(4.0126+5.00*n_{He})\\\\7.314+3.60n_{He}=4.013+5.00*n_{He}\\\\7.314-4.013=5.00*n_{He}-3.60n_{He}\\\\n_{He}=\frac{3.3}{1.4}=2.358mol

In such a way, the volume of the compartment B is:

V_B=\frac{n_{He}RT}{P_B}=\frac{2.358mol*0.082\frac{atm*L}{mol*K}*298.15K}{4.935atm}\\  \\V_B=11.68L

Finally, he mole fraction of He is:

x_{He}=\frac{2.358}{2.358+2.063}\\ \\x_{He}=0.533

Regards.

8 0
3 years ago
What process puts water vapor into the atmosphere?
cricket20 [7]

Answer:

transpiration

Explanation:

5 0
3 years ago
Read 2 more answers
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