A=Mass number=24
N=neutrons=13
Z=atomic number.
A=Z+N
24=Z+13
Z=24-13
Z=11
The atomic number is 11, and this atom is sodium.
Oxidation number is defined as the total number of electrons that are gained or lost by the atom to form a chemical bond.
the oxidation number of the compound H₂S is 0.
the sum of the oxidation numbers of the individual elements should add up to the oxidation number of the compound.
(oxidation number of H x 2 H ions) + oxidation number of S = 0
since we know the oxidation number of H, lets name the oxidation number of S = x
(+1 * 2 )+ (x) = 0
2 + x = 0
x = -2
oxidation number of S is -2
Answer and Explanation:
a. The equation of K of this reaction is shown below:-
3 A + 5 B + 4 C↔5 D + 7 E + F

b. The moles of compound F is shown below:-
3 A + 5 B + 4 C↔5 D + 7 E + F
2 moles
Now, the mole of produced is

Now, we will the value of c by using the above equation

After solving the above equation we will get
0.5 moles
Au :)
Pb + Cu(2+)---> Pb(2+) + Cu
Mg + Cu(2+)---> Mg(2+) + Cu
2Na + Cu(2+) ---> 2Na(+) + Cu
Au + Cu(2+) ---> (this reaction is not possible)
As you progress up any column on the periodic table the atomic radius gets smaller. Fluorine is a very small atom because it has very few electrons and Iodine is a very large atomic radius because it has many electrons.