Answer:
I think this is it.
Explanation:
As all the mass of other molecules are given and we have to find the mass of hydrogen so total subtracted by carbon and oxygen.
When the charged balloon is brought near the wall, it repels some of the negatively charged electrons in that part of the wall. Therefore, that part of the wall is left repelled.
<u>Explanation</u>:
- Balloons don't stick to walls. However, if you rub the balloon on an appropriate piece of material such as clothing or a wall, electrons are pulled from the other material to the balloon.
- The balloon now as more electrons than normal and therefore has an overall negative charge. Two balloons like this will repel each other.
- The other material now has an overall positive charge. Because opposite charges attract, the balloon will now appear to stick to the other material. If you didn't rub the balloon first, it's charge would be neutral and it wouldn't stick to the wall.
A) Ca(OH)2 + CO2 —> CaCO3 + H2O
B) when Ca(OH)2 is reacted with CO2, the CaCO3 produced is a precipitate which turns the solution milky
Answer:

Explanation:
Hello!
In this case, since the reactions between NaOH and the acids are:

Whereas we can see the 1:1 and 2:1 mole ratios between NaOH and HCl and H2SO4 respectively. In such a way, at the equivalence point we realize that:

Best regards!
Answer:
Explanation:
Given the equation:
![\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B9.8%28%5Cpm0.3%29-2.31%28%5Cpm%200.01%29%5D%7D%7B8.5%28%5Cpm0.6%29%7D)
The absolute uncertainty in a measurement is the term used to describe the degree of inaccuracy.
The first step is to determine the algebraic value on the numerator.
Algebraic value = 9.8 - 231
= 7.49
The absolute uncertainty = 
absolute uncertainty = 
= 
= 0.300167
∴
[9.8(±0.3) - 2.31(±0.01)] = 7.49(±0.300167)
The division process now is:
![\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= \dfrac{7.49 (\pm 0.300167)}{8.5 (\pm0.6)}](https://tex.z-dn.net/?f=%5Cimplies%20%5Cdfrac%7B%5B9.8%28%5Cpm0.3%29-2.31%28%5Cpm%200.01%29%5D%7D%7B8.5%28%5Cpm0.6%29%7D%3D%20%5Cdfrac%7B7.49%20%28%5Cpm%200.300167%29%7D%7B8.5%20%28%5Cpm0.6%29%7D)
Relative uncertainty = 
Relative uncertainty = ±4.007565% , ±7.058824%




≅ 8%
The algebraic value = 
= 0.881176
≅ 0.88
The percentage of the relative uncertainty =
By cross multiplying:




Finally:
![\mathbf{\implies \dfrac{[9.8(\pm0.3)-2.31(\pm 0.01)]}{8.5(\pm0.6)}= 0.88 \pm (0.07) \pm 8\%}](https://tex.z-dn.net/?f=%5Cmathbf%7B%5Cimplies%20%5Cdfrac%7B%5B9.8%28%5Cpm0.3%29-2.31%28%5Cpm%200.01%29%5D%7D%7B8.5%28%5Cpm0.6%29%7D%3D%200.88%20%5Cpm%20%280.07%29%20%5Cpm%208%5C%25%7D)