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3 years ago

Why are strong forces able to hold atomic nuclei together?

1 answer:

4 0

The nucleons(protons and neutrons) are held together by means of this strong force. If this strong never existed, all the nucleus will blow themselves due to strong repulsive force between protons(neutron has no charge).
Thats it!
If I explain beyond, it will surely bounce off your head. Anyways, if you wanna know more bout it, ping me. (:

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Carlos gives a grocery cart a 60-N push. The cart has a mass of 40 kg. What is the cart's acceleration?

andre [41]

<h3>Answer:</h3>

1.5 m/s²

<h3>Explanation:</h3>

We are given;

Force as 60 N

Mass of the Cart as 40 kg

We are required to calculate the acceleration of the cart.

From the newton's second law of motion, the rate of change in momentum is directly proportional to the resultant force.
That is, F = ma , where m is the mass and a is the acceleration

Rearranging the formula we can calculate acceleration, a

a = F ÷ m

= 60 N ÷ 40 kg

= 1.5 m/s²

Therefore, the acceleration of the cart is 1.5 m/s²

3 0

3 years ago

Please help have due very soon?thank you

Andru [333]

The answer is :78 I think

8 0

3 years ago

The light from Star 1 reaches Star 3 in 138 years and Star 2 in 63 years. Which of these conclusions about the stars is correct?

krek1111 [17]

The correct answer is A

6 0

3 years ago

1. A car travels a distance of 200 m in 4 seconds. What is the velocity of the car?

dybincka [34]

Answer:

velocity = distance / time taken

= 200/4

= 50 m/s

is the correct answer

3 0

3 years ago

A wheel on a car is rolling without slipping along level ground. The speed of the car is 36 m/s. The wheel has an outer diameter

lutik1710 [3]

Answer:

The speed of the top of the wheel is twice the speed of the car.

That is: 72 m/s

Explanation:

To find the speed of the top of the wheel, we need to combine to velocities: the tangential velocity of the rotating wheel due to rotational motion $(v_t=\omega\,R=\omega\,(0.25\,m)\,)$ - with $\omega$ being the wheel's angular velocity,

plus the velocity due to the translation of the center of mass (v = 36 m/s).

The wheel's angular velocity (in radians per second) can be obtained using the tangential velocity for the pure rotational motion and it equals: $\omega=\frac{v_t}{r} =\frac{36}{0.25} \,s^{-1}$

Then the addition of these two velocities equals:

$\omega\,R+v=\frac{36}{0.25} (0.25)\,\,\frac{m}{s} +36\,\,\frac{m}{s} =72\,\,\frac{m}{s}$

7 0

3 years ago