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astraxan [27]
3 years ago
14

What was the first major action Roosevelt took AFTER he was inaugurated (sworn in as president)

Physics
2 answers:
Marysya12 [62]3 years ago
7 0

Answer:

the second one i guess????

Explanation:

irina [24]3 years ago
5 0

Answer:

He closed all of the nation’s banks and ordered inspections

Explanation:

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An electromagnetic wave traveling through a vacuum has a wavelength of 1.5 × 10-1 meter. What is the period of this wave?
LiRa [457]

Answer: (1) 5.0 x 10^ -10 s

Explanation:

1.5 x 10^-1 m / 3 x 10^8 = .5 x 10^-9

= 5 x 10^-10

8 0
3 years ago
. Take a stick of length one and denote it by the unit interval [0, 1]. Pick two i.i.d. Uniform(0, 1) random variables U and V a
BartSMP [9]

Answer:

What is the expected value of L = 1/3

Explanation:

kindly check the attached file below.

5 0
4 years ago
The lonely deer was quietly nibbling grass. What type of level of organization would this be?Organism,Population,Community,Ecosy
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3 years ago
An object has rotational inertia I. The object, initially at rest, begins to rotate with a constant angular acceleration of magn
butalik [34]

Answer:

Explanation:

initial angular velocity, ωo = 0

angular acceleration = α

time = t

let the angular velocity after time t is ω.

Use first equation of motion for rotational motion

ω = o + α t

ω = αt

The angular momentum is given by

Angular momentum = moment of inertia x angular velocity

L = I x ω

L = I x αt

L = I α t

3 0
3 years ago
A (B + 25.0) g mass is hung on a spring. As a result, the spring stretches (8.50 A) cm. If the object is then pulled an addition
Morgarella [4.7K]

Answer:

Time period of the osculation will be 2.1371 sec

Explanation:

We have given mass m = (B+25)

And the spring is stretched by (8.5 A )

Here A = 13 and B = 427

So mass m = 427+25 = 452 gram = 0.452 kg

Spring stretched x= 8.5×13 = 110.5 cm

As there is additional streching of spring by 3 cm

So new x = 110.5+3 = 113.5 = 1.135 m

Now we know that force is given by F = mg

And we also know that F = Kx

So mg=Kx

K=\frac{mg}{x}=\frac{0.452\times 9.8}{1.135}=3.90N/m

Now we know that \omega =\sqrt{\frac{K}{m}}

So \frac{2\pi }{T} =\sqrt{\frac{K}{m}}

\frac{2\times 3.14 }{T} =\sqrt{\frac{3.90}{0.452}}

T=2.1371sec

8 0
3 years ago
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