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Crazy boy [7]
3 years ago
5

PLEASE HELP ME QUICK

Chemistry
1 answer:
Mama L [17]3 years ago
6 0

Answer:

b. decreases

C. neither a physical change nor a chemical change

light work

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At sea level, where the pressure was 104 kPa and temperature 21.1 ºC, a certain mass of air occupies 2.0 m3 . To what volume wil
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The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

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The combined gas equation is,

\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}

where,

P_1 = initial pressure of gas = 104 kPa

P_2 = final pressure of gas = 52 kPa

V_1 = initial volume of gas = 2.0m^3

V_2 = final volume of gas = ?

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Now put all the given values in the above equation, we get:

\frac{104 kPa\times 2.0m^3}{294.1 K}=\frac{52 kPa\times V_2}{268 K}

V_2=3.64 m^3

The volume of air at where the pressure and temperature are  52 kPa, -5.0 ºC is 3.64 m^3.

3 0
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