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vlada-n [284]
3 years ago
10

A 135 g sample of H20 at 85°C is cooled. The water loses a total of 15 kJ of energy in the cooling

Chemistry
1 answer:
Andre45 [30]3 years ago
8 0

Answer:

B. 58°C

Explanation:

Hello,

In this case, the relationship among heat, mass, specific heat and temperature for water is mathematically by:

Q=mCp\Delta T=mCp(T_2-T_1)

In such a way, solving for the final temperature T_2 we obtain:

T_2=T_1+\frac{Q}{mCp}

Therefore, we final temperature is computed as follows, considering that the involved heat is negative as it is lost for water:

T_2=85\°C+\frac{-15kJ*\frac{1000J}{1kJ} }{135g*4.184\frac{J}{g\°C} }\\\\T_2=58\°C

Thereby, answer is B. 58°C .

Regards.

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