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Aleksandr-060686 [28]
3 years ago
5

Hydrogen peroxide, H2O2, is common in many households and is used as a bleaching agent. It usually comes in a dark, opaque bottl

e. When exposed to heat or light, hydrogen peroxide will decompose according to the reaction:
2 H2O2→2 H2O + O2

Iron Nitrate has been shown to be an effective catalyst to accelerate the decomposition process, and sodium phosphate can inhibit the effects of this catalytic effect.

Naturally, the consumer does not want their hydrogen peroxide to decompose. Consider the factors affecting reaction rate that you learned about in this lesson. What should the consumer should do to prevent the decomposition of hydrogen peroxide?. For example, should the hydrogen peroxide be stored in a warm or cool location? Use scientific reasoning to support your response.
Chemistry
1 answer:
sergij07 [2.7K]3 years ago
8 0

Answer:

Hydrogen peroxide should be stored in

1) a cool environment

2) with amber bottles away from sunlight

3) with little drops of sodium phosphate

Explanation:

It has been confirmed that heat and light aids in the decomposition of hydrogen peroxide according to the equation; 2H2O2→2 H2O + O2.

This means that hydrogen peroxide must be stored in a cool place. This will reduce its rate of decomposition. Secondly, it should be stored in amber bottles away from light since light also aids in its decomposition.

Thirdly, drops of sodium phosphate may be added to prevent its catalytic decomposition during storage.

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17. SiH3P<br> How do you create a Lewis structure for this formula?
Marianna [84]

Answer:

See attached picture.

Explanation:

Hello,

In this case, considering that Lewis structures are drawn in order to show up the bonding among equal or different atoms via their valence electrons, since hydrogen has one valence electron, silicon four and phosphorous five, the most suitable way to draw and attain the octet for both silicon and phosphorous is by bonding them via a double bond, one hydrogen bonded to the phosphorous and two hydrogen atoms bonded to the silicon as shown on the attached picture, wherein you can count eight electrons for both phosphorous and silicon.

Best regards.

7 0
3 years ago
Write the henderson-hasselbalch equation for a propanoic acid solution (ch3ch2co2h, pa=4. 874)
Mariana [72]

The Henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

<h3>What is Henderson Hasselbalch Equation ?</h3>

It is expressed as:

pH = pKa + log([A-]/[HA].

where,

[A-] is molar concentration of conjugate base and

[HA] is molar concentration of weak acid.

Given,

pH = 5.30

Substitute the value in the Henderson Hasselbalch equation

5.30 = 4.874 + log[A-]/ [HA]

log[A-]/[HA] = 5.30 - 4.874

[A-]/[HA] = 10^ 0.426

[A-]/[HA] = 2.7

Thus from the conclusion we can say that The henderson-hasselbalch equation for a propanoic acid solution is expressed as [A-]/[HA] = 2.7.

Learn more about Henderson Hasselbalch equation here:

brainly.com/question/13423434

#SPJ4

7 0
1 year ago
A compound decomposes by a first-order process. What is the half-life of the compound if 25.0% of the compound decomposes in 60.
amid [387]

Answer : The half-life of the compound is, 145 years.

Explanation :

First we have to calculate the rate constant.

Expression for rate law for first order kinetics is given by:

k=\frac{2.303}{t}\log\frac{a}{a-x}

where,

k = rate constant  = ?

t = time passed by the sample  = 60.0 min

a = let initial amount of the reactant  = 100 g

a - x = amount left after decay process = 100 - 25 = 75 g

Now put all the given values in above equation, we get

k=\frac{2.303}{60.0}\log\frac{100g}{75g}

k=4.79\times 10^{-3}\text{ years}^{-1}

Now we have to calculate the half-life of the compound.

k=\frac{0.693}{t_{1/2}}

4.79\times 10^{-3}\text{ years}^{-1}=\frac{0.693}{t_{1/2}}

t_{1/2}=144.676\text{ years}\approx 145\text{ years}

Therefore, the half-life of the compound is, 145 years.

8 0
3 years ago
The hydrogen gas formed in a chemical reaction is collected over water at 30.0 ∘c at a total pressure of 734 mmhg . part a what
In-s [12.5K]

At a temperature of 30 deg C, the vapour pressure of water H2O is about 32 mm Hg. Therefore at a total pressure f 734 mm Hg, the partial pressure of the Hydrogen gas collected is:

<span>P Hydrogen = 734 mm Hg – 32 mm Hg = 702 mm Hg</span>

6 0
3 years ago
Read 2 more answers
A 50.0 mL solution of 0.141 M KOH is titrated with 0.282 M HCl . Calculate the pH of the solution after the addition of each of
Kobotan [32]

Answer:

pH =1 2.84

Explanation:

First we have to start with the <u>reaction</u> between HCl and KOH:

HCl~+~KOH->~H_2O~+~KCl

Now <u>for example, we can use a volume of 10 mL of HCl</u>. So, we can calculate the moles using the <u>molarity equation</u>:

M=\frac{mol}{L}

We know that 10mL=0.01L and we have the concentration of the HCl 0.282M, when we plug the values into the equation we got:

0.282M=\frac{mol}{0.01L}

mol=0.282*0.01

mol=0.00282

We can do the same for the KOH values (50mL=0.05L and 0.141M).

0.141M=\frac{mol}{0.05L}

mol=0.141*0.05

mol=0.00705

So, we have so far <u>0.00282 mol of HCl</u> and <u>0.00705 mol of KOH</u>. If we check the reaction we have a <u>molar ratio 1:1</u>, therefore if we have 0.00282 mol of HCl we will need 0.00282 mol of KOH, so we will have an <u>excess of KOH</u>. This excess can be calculated if we <u>substract</u> the amount of moles:

0.00705-0.00282=0.00423mol~of~KOH

Now, if we want to calculate the pH value we will need a <u>concentration</u>, in this case KOH is in excess, so we have to calculate the <u>concentration of KOH</u>. For this, we already have the moles of KOH that remains left, now we need the <u>total volume</u>:

Total~volume=50mL+10mL=60mL

60mL=0.06L

Now we can calculate the concentration:

M=\frac{0.00423mol}{0.06L}

M=0.0705

Now, we can <u>calculate the pOH</u> (to calculate the pH), so:

pOH=-Log(0.0705)

pOH=1.15

Now we can <u>calculate the pH value</u>:

14=~pH~+~pOH

pH=14-1.15=12.84

8 0
3 years ago
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