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maks197457 [2]
2 years ago
10

Mining companies use this reaction to obtain iron from iron ore: Fe2O3(s)+3CO(g) → 2Fe(s)+3CO2(g) The reaction of 177 g of Fe2O3

with 82.8 g of CO produces 72.7 g of Fe. Calculate the theoretical yield of solid iron.
ANSWER: 110. g Fe
Chemistry
1 answer:
dezoksy [38]2 years ago
7 0

Answer:

The theoretical yield of solid iron is 110.05 grams

Explanation:

<u>Step 1</u>: The balanced equation

Fe2O3(s)+3CO(g) → 2Fe(s)+3CO2(g)

This means for 1 mole of Fe2O3 consumed, there is 3 moles of CO needed to produce 2 moles of Fe and 3 moles of CO2

<u>Step 2</u>: given data

Mass of Fe2O3 = 177g

MM of Fe2O3 = 159.69g/mole

Mass of CO = 82.8g

MM of CO = 28.01

Mass of CO2 = 72.7g

MM of CO2 = 44.01 g/mole

Mass of Fe = TO BE DETERMINED

MM of Fe = 55.845 g/mole

<u>Step 3:</u> Calculating moles

Moles = mass / Molar mass

moles Fe2O3 = 177/159.69 = 1.1084 moles

moles CO = 82.8/28.01 = 2.9561 moles

⇒ CO is the limiting reactant ; Fe2O3 is the reactant in excess (there will remain 0.123 moles)

<u>Step 4</u>: Calculating moles of Fe

There will be produced 2 moles of Fe if there is consumed 3 moles of CO

If there is consumed 2.9561 moles of Fe, there is produced 1.9707 moles of Fe

<u>Step 5:</u> Calculating mass of Fe

mass = moles * Molar mass

mass of Fe = 1.9707 moles * 55.845 = 110.05 grams

The theoretical yield of solid iron is 110.05 grams

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