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kakasveta [241]
2 years ago
15

What kind of waves do light waves travel in and how do they move

Chemistry
1 answer:
IgorLugansk [536]2 years ago
8 0
Light is one form of energy that travels in electromagnetic waves. This energy is both magnetic and electrical. There are many different types of electromagnetic (EM) waves.
You might be interested in
How is a battery and a banana the same when considering energy?
emmainna [20.7K]

A battery and a banana are the same when considering energy:

A battery when connected to a device produces electro-chemical reactions and contains one or more cells. The same thing can be tried out with fruits also. There are many fruits which can be taken into account. A lemon shows less amount of voltage when seen through a multimeter rather than a banana which shows a higher voltage. This was because of the acid present in the a fully ripped banana. The acid is called ascorbic acid. This acid has a higher pH level than compared to the pH of the citric acid found in lemon.  

This shows that a banana plant is not so expensive and reliable for the production of renewable energy and a battery is also inexpensive, reliable and stable.

4 0
4 years ago
How much hcl must be added to a liter of buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate to result in a buffe
yaroslaw [1]

For a liter of a buffer that is 1. 5 m in acetic acid and 0. 70 m in sodium acetate, and with a  result in a buffer pH of 4.01, the moles of HCl required is mathematically given as x=0.313mol

<h3>What is the result in a buffer ph of 4. 01?</h3>

Generally, the equation for the pH   is mathematically given as

pH=pKa+logsalt/acid

Generally, the equation for the Chemical Reaction   is mathematically given as

HCl+CH3CooNa---->NaCl+CH3OOH

Therefore

4.01=4.74+log\frac{0.8-x}{1.3+x}

-0.52=log\frac{0.8-x}{1.3+x}

x=0.313mol

In conclusion, The moles of HCl required is

x=0.313mol

Read more about Chemical Reaction

brainly.com/question/6876669

8 0
2 years ago
At 25°C, 100 g of water will be saturated with 35.7 g of NaCl. Which word below describes the solution of 1.55 mol of NaCl disso
erica [24]
1) The saturation point at 25°C is 35.7 g of NaCl / 100 g of water => 35.7 %

Under normal circumstances water will not accept more salt than that.

2) The solution with 1.55 mol of NaCl dissolved in 250 mL of water =>

molar mass of NaCl = 22.99 g/mol + 35.45 g/mol = 58.44 g/mol

grams of NaCl = 1.55 mol * (molar mass of NaCl) = 1.55mol * 58.44 g/mol = 90.58 grams of NaCl


grams of water = 250 mL * 1 g/mL = 250 g/g.

Concentration of the solution:  [90.58 g NaCl / 250 g H2O] * 100 = 36.23 %

3) Conclusion: the solution has more salt than the saturation value. This means that the solution is supersaturated.

Supersaturation is a special condition, which is unstable, but that is not part of the questions.

The answer is supersaturated, 
5 0
4 years ago
What is the number of molecules present in 1.12 dm^3 of nitrogen gas at STP​
Anuta_ua [19.1K]

Answer:

\huge\boxed{\sf No.\ of\ molecules = 3 * 10\²\² \ molecules}

Explanation:

<u>Given Data:</u>

Volume = v = 1.12 dm³ = 1.12 L

Density of nitrogen at STP = D = 1.25 g / L

Molar mass = M = 14 * 2 = 28 g / mol

Avogadro's Number = \tt{N_{A}} = 6.023 * 10²³ mol⁻¹

<u>Required:</u>

No. of molecules = ?

<u>Formula:</u>

\tt{No. \ of \ molecules = \frac{Density * Volume}{Molar\ Mass} * N_{A}}

<u>Solution:</u>

No. of molecules = (1.25*1.12) / 28 * (6.023 * 10²³)

No. of molecules = ( 1.4 / 28 ) * 6.023 * 10²³

No. of molecules = 0.05 * 6.023 * 10²³

No. of molecules = 0.3 * 10²³

No. of molecules = 3 * 10²² molecules

\rule[225]{225}{2}

Hope this helped!

<h3>~AH1807</h3>
4 0
3 years ago
Write balanced chemical equations for the sequence of reactions that oxalic acid can undergo when it's dissolved in water.
Mashcka [7]

Answer and Explanation:

The balanced chemical equations are as follows:

The chemical formula of oxalic is  H_2C_2O_4

In the case when oxalic acts reacted with the water so here the oxalic acid eliminates one proton that leads to the development of mono acids

After that, the second step derives that when oxalic acid is in aqueous solution eliminates other proton so it represent the polyprotic acid

Now the chemical equations are as follows:

Elimination of one proton

H_2C_2O_4(aq)+H_2O(l)  \rightarrow H_2C_2O_4^-(aq) + H_3O^+(aq)

Now the elimination of other proton

HC_2O_4^-(aq)+H_2O(l)  \rightarrow C_2O_4^2^-(aq) + H_3O^+(aq)

7 0
3 years ago
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