What kind of scientist would study the effects of acid rain on marble statues?

What is the total charge of the nucleus of a carbon atom?<br> (1) –6 (3) +6<br> (2) 0 (4) +12

NeX [460]

Carbon atomic number ⇒ 6
Carbon mass number ⇒ 12.

Carbon atomic number - Carbon mass number = number of neutrons.
12 - 6 = 6 neutrons.

Proton charge ⇒ +1

The total charge of the nucleus of a carbon atom ⇒⇒⇒ +6.

So the naswer is (3) +6

3 0

3 years ago

Calculate the solubility of carbon dioxide at 400 kPa.

BaLLatris [955]

The solubility of carbon dioxide at 400 kPa at room temperature is ;

( B ) 0.61 CO2/L

<u>Given data </u>

pressure of CO₂ = 400 Kpa = 3.95 atm

Kh of CO₂ = 3.3 * 10⁻² mol/L.atm

<h3>Calculate the solubility of carbon dioxide </h3>

Solubility = pressure * Kh value of CO₂

= 3.95 atm * 3.3 * 10⁻² mol / L.atm

= 0.13 mol/l CO₂

= 0.61 CO₂ / L

Hence we can conclude that the solubility of CO₂ at 400 kPa is 0.13 mol/l CO₂.

Learn more about solubility : brainly.com/question/23946616

From the options the closest answer is ( B ) 0.61 CO₂ / L

7 0

2 years ago

Carbon burns in the presence of oxygen to give carbon dioxide. Which chemical equation describes this reaction?

Vlad1618 [11]

Answer: option B.

carbon + oxygen → carbon dioxide

Explanation:

8 0

3 years ago

Read 2 more answers

How well can you apply Charles’s law to this sample of gas that experiences changes in pressure and volume? Assume that pressure

Phoenix [80]

Answer:

As temperature increases the volume of given amount of gas increases while pressure and number of moles remain constant.

Explanation:

According to the charle's law,

The volume of given amount of gas is directly proportional to the temperature at constant pressure and number of moles of gas.

Mathematical expression:

V ∝ T

V = KT

V/T = K

When temperature changes from T₁ to T₂ and volume changes from V₁ to V₂.

V₁/T₁ = K V₂/T₂ = K

or

V₁/T₁ = V₂/T₂

Thus, the ratio of volume and temperature remain constant for constant amount of gas at constant pressure.

6 0

3 years ago

Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb ( NO 3 ) 2

nikklg [1K]

Answer : The volume of $NH_4I$ solution required is, 2.93 L

The number of moles of $PbI_2$ formed from the reaction is, 0.662 moles.

Explanation :

First we have to calculate the initial moles of $Pb(NO_3)_2$ .

$\text{Moles of }Pb(NO_3)_2=\text{Concentration of }Pb(NO_3)_2\times \text{Volume of solution}$

$\text{Moles of }Pb(NO_3)_2=0.700M\times 0.945L=0.662mol$

Now we have to calculate the moles of $NH_4I$

The balanced chemical reaction is:

$Pb(NO_3)_2(aq)+2NH_4I(aq)\rightarrow PbI_2(s)+2NH_4NO_3(aq)$

From the balanced chemical reaction we conclude that,

As, 1 mole of $Pb(NO_3)_2$ react with 2 moles of $NH_4I$

So, 0.662 mole of $Pb(NO_3)_2$ react with $0.662\times 2=1.32$ moles of $NH_4I$

Now we have to calculate the volume of $NH_4I$

$\text{Volume of }NH_4I=\frac{\text{Moles of }NH_4I}{\text{Concentration of }NH_4I}$

$\text{Volume of }NH_4I=\frac{1.32mol}{0.450mol/L}=2.93L$

Now we have to calculate the moles of $PbI_2$

From the balanced chemical reaction we conclude that,

As, 1 mole of $Pb(NO_3)_2$ react to give 1 moles of $PbI_2$

So, 0.662 mole of $Pb(NO_3)_2$ react to give 0.662 moles of $PbI_2$

Thus, the number of moles of $PbI_2$ formed from the reaction is, 0.662 moles.

7 0

3 years ago