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iogann1982 [59]
3 years ago
7

1. What metal is oxidized in the most common dry cell? zinc iron carbon copper

Chemistry
2 answers:
GREYUIT [131]3 years ago
4 0

Answer:

the correct answer is zinc

kompoz [17]3 years ago
4 0
Zinc is the correct I think
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Iodine monochloride (ICl) has a higher boiling point than bromine (Br2) partly because iodine monochloride is a(n)
tekilochka [14]

Answer: polar molecule.

Explanation:

The boiling point is the temperature at which the vapor pressure of a liquid equals the external pressure surrounding the liquid. The boiling point is dependent on the type of forces present.

Iodine monochloride (ICl) is a polar molecule due to the difference in electronegativities of iodine and chlorine. Thus the molecules are bonded by strong dipole dipole forces. Thus a higher temperature is needed to generate enough vapor pressure.

Bromine (Br_2) is a non polar molecule as there is no electronegativity difference between two bromine atoms. The molecules are bonded by weak vanderwaal forces and thus has low boiling point.

7 0
2 years ago
What air moves horizontally or parallel to the ground?
weqwewe [10]

Wind, air that moves to the ground

7 0
3 years ago
A friend tells you that plants grow and gain mass only because of the nutrients they pull out of the soil. It this statement tru
Nutka1998 [239]
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5 0
3 years ago
Which of these methods could be used to separate an insoluble solid from a soluble solid? Melting the mixture and then using a f
I am Lyosha [343]

Answer : The correct option is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.

Explanation :

"The given mixture contains a soluble solid and an insoluble solid.

When water is added to this mixture, the soluble solid will get dissolved in water whereas the insoluble solid will remain as it is.

This will give us a heterogeneous mixture where we can see 2 distinct phases , one containing the dissolved solid and the other having undissolved solid.

In order to separate these 2 phases, we can use a simple filtration method.

When the mixture is filtered, we will get solution having soluble solid and the insoluble solid will remain on the filter paper.

This will separate the 2 solids.

To regenerate the dissolved solid, we can evaporate the water by heating it. This will give us back our original soluble solid.

Therefore, the only option that is consistent with this method is "Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid"

8 0
3 years ago
Plz help me with this:
In-s [12.5K]

Answer:

1) H 1s^1

2) [Ar] 3d⁸ 4s²

3) [He] 2s2 2p3

4) [Kr] 4d10 5s2 5p5

5) [Ar] 4s² and [Ar] 4s²

6) [He] 2s2 2p2

7)  [He] 2s² 2p⁴

8) [Ar] 3d7 4s2

9) [Kr] 4d¹⁰ 5s¹  

10) [Ne] 3s² 3p⁶

Explanation:

7 0
3 years ago
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