How many molecules of O2 are there in 2.0 moles of oxygen?

A box of cleaning supplies weighs 15 N. If the box is lifted a distance of 0.60 m, how much work is done?

Nady [450]

Work Done = force x displacement. So in this case the 15N is the force (because weight is a force) and 0.60m is the displacement. Therefore 15 x 0.6 = 9 Joules of work done (btw, work done can also be referred to as energy transferred)

3 0

4 years ago

Read 2 more answers

C3H18 +<br> O2<br> +<br> CO2 + H2O<br> Balance equation

dimulka [17.4K]

Answer:

2C3H18 + 15O2 ---->6CO2 +18H2O

Explanation:

the number of reactant must be equal to the number of product.

7 0

3 years ago

Calculate the volume of chlorine molecules produced at room temperature and pressure, when 234g of sodium chloride are electroly

rewona [7]

The volume of chlorine molecules produced at STP would be 96 dm³.

<h3>Stoichiometric problem</h3>

Sodium chloride ionizes during electrolysis to produce sodium and chlorine ions as follows:

$NaCl --- > Na^+ + Cl^-$

This means that 1 mole of sodium chloride will produce 1 mole of sodium ion and 1 mole of chlorine ion respectively.

Recall that: mole = mass/molar mass

Hence, 234 g of sodium chloride will give:

234/58.44 = 4.00 moles.

Thus, the equivalent number of moles of chlorine produced by 234 g of sodium chloride will be 4 moles.

Recall that:

1 mole of every gas at Standard Temperature and Pressure = 24 Liters.

Hence:

4 moles of chlorine = 4 x 24 = 96 Liters or 96 dm³.

More on stoichiometric problems can be found here: brainly.com/question/14465605

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4 0

2 years ago

B) Ethane has the formula C2H6. In terms of electronic structure,

k0ka [10]

Answer:

There is one single covalent bond between two carbon atoms.

Explanation:

We know that sharing of electrons form covalent bonds.

If we look upon K,L,M ,N shells of the carbon and hydrogen atoms.

We found that Hydrogen is having only $1$ electron in K shell.

And Carbon on the other hand is having $2$ electrons in K shell and $4$ electrons in L shell.

So carbon have $4$ valence electrons,and it can share $4$ bonds with any relevant atom to complete its octet.

And Hydrogen requires $1$ electron to complete its doublet.

Alkane general formula $C_{n}H_{2n+2}$

For ethane $n=2$

$C_{2}H_{4+2}$ $=$ $C_{2}H_{6}$

$1$ Carbon atom is shared by $3$ Hydrogen.

The remaining one electron $(4-3)=1$ of carbon will be shared with another carbon atom.

An image of the sharing of electrons attached below,

Hence we have only $1$ covalent bond between the two.

5 0

4 years ago

Th e enzyme-catalyzed conversion of a substrate at 25°C has a Michaelis constant of 0.045 mol dm−3. Th e rate of the reaction is

Elis [28]

Answer:

$1.620\times 10^{-3} mol/dm^3 s$ is the maximum velocity of this reaction.

Explanation:

Michaelis–Menten 's equation:

$v=V_{max}\times \frac{[S]}{K_m+[S]}=k_{cat}[E_o]\times \frac{[S]}{K_m+[S]}$

$V_{max}=k_{cat}[E_o]$

v = rate of formation of products =

[S] = Concatenation of substrate

$[K_m]$ = Michaelis constant

$V_{max}$ = Maximum rate achieved

$k_{cat}$ = Catalytic rate of the system

$[E_o]$ = Initial concentration of enzyme

We have :

$K_m=0.045 mol/dm^3$

$v=1.15 mmol/dm^3 s=1.15\times 10^{-3} mol/dm^3 s$

$[S]=0.110 mol/dm^3$

$v=V_{max}\times \frac{[S]}{K_m+[S]}$

$1.15\times 10^{-3} mol/dm^3 s=V_{max}\times \frac{0.110 mol/dm^3}{[(0.045 mol/dm^3)+(0.110 mol/dm^3)]}$

$V_{max}=\frac{1.15\times 10^{-3} mol/dm^3 s\times [(0.045 mol/dm^3)+(0.110 mol/dm^3)]}{0.110 mol/dm^3}=1.620\times 10^{-3} mol/dm^3 s$

$1.620\times 10^{-3} mol/dm^3 s$ is the maximum velocity of this reaction.

8 0

3 years ago