How many molecules of O2 are there in 2.0 moles of oxygen?

If you combine 230.0 mL 230.0 mL of water at 25.00 ∘ C 25.00 ∘C and 120.0 mL 120.0 mL of water at 95.00 ∘ C, 95.00 ∘C, what is t

Thepotemich [5.8K]

<u>Answer:</u> The final temperature of the mixture is 49°C

<u>Explanation:</u>

To calculate the mass of water, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

<u>For cold water:</u>

Density of cold water = 1 g/mL

Volume of cold water = 230.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{230.0mL}\\\\\text{Mass of water}=(1g/mL\times 230.0mL)=230g$

<u>For hot water:</u>

Density of hot water = 1 g/mL

Volume of hot water = 120.0 mL

Putting values in above equation, we get:

$1g/mL=\frac{\text{Mass of water}}{120.0mL}\\\\\text{Mass of water}=(1g/mL\times 120.0mL)=120g$

When hot water is mixed with cold water, the amount of heat released by hot water will be equal to the amount of heat absorbed by cold water.

$Heat_{\text{absorbed}}=Heat_{\text{released}}$

The equation used to calculate heat released or absorbed follows:

$Q=m\times c\times \Delta T=m\times c\times (T_{final}-T_{initial})$

$m_1\times c\times (T_{final}-T_1)=-[m_2\times c\times (T_{final}-T_2)]$ ......(1)

where,

q = heat absorbed or released

$m_1$ = mass of hot water = 120 g

$m_2$ = mass of cold water = 230 g

$T_{final}$ = final temperature = ?°C

$T_1$ = initial temperature of hot water = 95°C

$T_2$ = initial temperature of cold water = 25°C

c = specific heat of water = 4.186 J/g°C

Putting values in equation 1, we get:

$120\times 4.186\times (T_{final}-95)=-[230\times 4.186\times (T_{final}-25)]$

$T_{final}=49^oC$

Hence, the final temperature of the mixture is 49°C

4 0

4 years ago

The weight of a table as measured by a student is 20 kg.The

miskamm [114]

(20/23) times 100 is 87%

now the answer asks for percentage ERROR

100-87 =13

so answer is C

7 0

3 years ago

Read 2 more answers

Hello there!

Alenkasestr [34]

Answer:

Mass of carbon dioxide = 7.48 g

Explanation:

Given data:

Mass of lithium carbonate = 12.5 g

Mass of carbon dioxide produced = ?

Solution:

Chemical equation:

Li₂CO₃ → Li₂O + CO₂

Number of moles of Li₂CO₃:

Number of moles = mass/ molar mass

Number of moles = 12.5 g /73.89 g/mol

Number of moles = 0.17 mol

Now we will compare the moles of Li₂CO₃ with CO₂.

Li₂CO₃ : CO₂

1 : 1

0.17 : 0.17

Mass of carbon dioxide:

Mass of carbon dioxide = number of moles × molar mass

Mass of carbon dioxide = 0.17 mol × 44 g/mol

Mass of carbon dioxide = 7.48 g

4 0

3 years ago

At 741 torr and 44°C, 7.10 g of a gas occupy a volume of 5.40 L. What is the molar mass

amm1812

The molar mass of the gas is 35. glmol.

the molar mass of a chemical compound is described as the mass of a sample of that compound separated by the amount of substance in that sample, measured in moles.

The molar mass is a bulk, not molecular, effects of a substance.

<h3>What is molar mass and how is it calculated?</h3>

The molar mass is the mass of one mole of a sampling. To find the molar mass, count the atomic masses (atomic weights) of all of the atoms in the molecule. Find the atomic mass for each element by using the mass shown in the Periodic Table or table of atomic weights.

<h3>What is molar ?</h3>

Molar refers to the unit of concentration molarity, which is equivalent to the number of moles per liter of a solution. In chemistry, the word most often guides to molar concentration of a solute in a solution. Molar attention has the units mol/L or M.

To learn more about the molar mass, refer

brainly.com/question/15476873

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4 0

2 years ago

Is the photon is in the IR, UV or visible portion of the electromagnetic spectrum.

DiKsa [7]

Answer:

The different types of radiation are defined by the the amount of energy found in the photons. Radio waves have photons with low energies, microwave photons have a little more energy than radio waves, infrared photons have still more, then visible, ultraviolet, X-rays, and, the most energetic of all, gamma-rays.Explanation: hope this helps god bless you

8 0

2 years ago