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3 years ago

2(x – 3) – 5 = 4(x + 3) - 2x solve the given equation

Mathematics

2 answers:

rewona [7]3 years ago

8 0

2.(x - 3) - 5 = 4.(x + 3) - 2x

2x - 6 - 5 = 4x + 12 - 2x

2x - 4x + 2x = 12 + 6 + 5

4x - 4x = 23

0 = 23

Something is wrong, you must have wrote something wrong

dmitriy555 [2]3 years ago

4 0

Answer:0 does not =23 so no solution

Step-by-step explanation:

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butalik [34]

Step-by-step explanation:

m=5/7

m1=m2=5/7

L;y-(-2)=5/7(x-(-5)

y+2=5/7(x+5)

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3 years ago

PLSS HELP ME FIND THE SURFACE AREA OF THE TRIANGULAR PRISM <br><br> THXXSSSS AND HURRY PLS

aleksley [76]

Answer:

108m^2

Step-by-step explanation:

surface area of any shape: sum of the area of its sides.

area of cross section x 2 = 4 x 3 12 m^2

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3 years ago

The projected rate of increase in enrollment at a new branch of the UT-system is estimated by E ′ (t) = 12000(t + 9)−3/2 where E

nexus9112 [7]

Answer:

The projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

Step-by-step explanation:

Consider the provided projected rate.

$E'(t) = 12000(t + 9)^{\frac{-3}{2}}$

Integrate the above function.

$E(t) =\int 12000(t + 9)^{\frac{-3}{2}}dt$

$E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+c$

The initial enrollment is 2000, that means at t=0 the value of E(t)=2000.

$2000=-\frac{24000}{\left(0+9\right)^{\frac{1}{2}}}+c$

$2000=-\frac{24000}{3}+c$

$2000=-8000+c$

$c=10,000$

Therefore, $E(t) =-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

Now we need to find $\lim_{t \to \infty} E(t)$

$\lim_{t \to \infty} E(t)=-\frac{24000}{\left(t+9\right)^{\frac{1}{2}}}+10,000$

$\lim_{t \to \infty} E(t)=10,000$

Hence, the projected enrollment is $\lim_{t \to \infty} E(t)=10,000$

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2 years ago

The Woodman Firewood Company delivers natural firewood to homes in Manhattan,

ratelena [41]

Answer:

step by step and the dog got 10 fire wood

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2 years ago

Please help ! This is 7th grade math and I’ve been stuck on this question for 30 minutes!

FinnZ [79.3K]

$\dfrac{1}{22}\:\dfrac{\text{in}}{\text{hr}}$

Step-by-step explanation:

The amount of time from 10pm to 7am is 9 hours. However, the time indicated is 7:10am. Since there are 60 minutes in an hour, 10 min is equal to 1/6 of an hour. Therefore, the total time that the water level of the pool decreased is $9\frac{1}{6}$ hours or $\frac{55}{6}$ hours. To find the rate at which the water level decreased, we divide the change in the water (in inches) by the time it took to reach that level. So we write

rate of change $= \dfrac{\text{change\:in\:height}}{\text{change\:in\:time}}$

$\:\:\:\:\:\:\:= \dfrac{\frac{5}{12}\:\text{in}}{\frac{55}{6}\:\text{hrs}}$

$\:\:\:\:\:\:\:=\dfrac{5}{12}\cdot\dfrac{6}{55}\:\dfrac{\text{in}}{\text{hr}}$

$\:\:\:\:\:\:\:= \frac{1}{22}\:\dfrac{\text{in}}{\text{hr}}$

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3 years ago