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alexira [117]
3 years ago
5

Question 16 (6 points)

Chemistry
1 answer:
MakcuM [25]3 years ago
6 0

Answer:

1.) Fluorine

2.) Francium

3.) Nonmetals

4.) Metals

5.) Aluminum

6.) Helium

Explanation:

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Someone please help will mark as brainliest
Tju [1.3M]

Answer: The answer is D.

Explanation: The warm water will cause the sugar to dissolve quicker.

5 0
3 years ago
A certain element has only two naturally occurring isotopes: one with 18 neutrons and the other with 20 neutrons. The element fo
melamori03 [73]

Answer:

[Cl-18]⁻ & [Cl-20]⁻

Explanation:

By definition isotopes are elements with the same number of protons by different number of neutrons. Elements X-18 & X-20 have 17 protons and represent Chlorine isotopes Cl-18 & Cl-20 each with 17 protons and 18 electrons to give the isotopes a -1 oxidation state. Both isotope of chlorine have 7 electron in its valence shell and 10 electrons in its core structure.  Gaining 1 electron fills the valence octet and establishes a -1 oxidation state.

7 0
3 years ago
Which of the following is a chemical property of iron? It
astraxan [27]

Answer:

is capable of combining with oxygen to form iron oxide

4 0
3 years ago
You are given a solid that is a mixture of na2so4 and k2so4.
Murljashka [212]

Here we have to calculate the amount of SO_{4}^{2-} ion present in the sample.

In the sample solution 0.122g of SO_{4}^{2-} ion is present.

The reaction happens on addition of excess BaCl₂ in a sample solution of potassium sulfate (K₂SO₄) and sodium sulfate [(Na)₂SO₄] can be written as-

K₂SO₄ = 2K⁺ +  SO_{4}^{2-}

(Na)₂SO₄=2Na⁺ +  SO_{4}^{2-}

Thus, BaCl₂+  SO_{4}^{2-} = BaSO₄↓ + 2Cl⁻ .

(Na)₂SO₄ and  K₂SO₄ is highly soluble in water and the precipitation or the filtrate is due to the BaSO₄ only. As a precipitation appears due to addition of excess BaCl₂ thus the total amount of  SO_{4}^{2-} ion is precipitated in this reaction.  

The precipitate i.e. barium sulfate (BaSO₄)is formed in the reaction which have the mass 0.298g.

Now the molecular weight of BaSO₄ is 233.3 g/mol.

We know the molecular weight of sulfate ion (SO_{4}^{2-}) is 96.06 g/mol. Thus in 1 mole of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present.

Or. we may write in 233.3 g of BaSO₄ 96.06 g of SO_{4}^{2-} ion is present. So in 1 g of BaSO₄ \frac{96.06}{233.3}=0.411 g of SO_{4}^{2-} ion is present.

Or, in 0.298 g of the filtered mass (0.298×0.411)=0.122g of SO_{4}^{2-} ion is present.        

5 0
3 years ago
Which of the following is NOT a property of an acid
ipn [44]
The answer is B. Acid turns blue litmus paper to red
4 0
3 years ago
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