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lakkis [162]
3 years ago
9

Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq

uation H 2 S O 4 + 2 N a O H ⟶ 2 H 2 O + N a 2 S O 4 If you require 29.09 mL of 0.639 M N a O H solution to titrate 213.8 mL of H 2 S O 4 solution, what is the concentration of the H 2 S O 4 solution?
Chemistry
1 answer:
pogonyaev3 years ago
5 0

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

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Answer:

A crystal or crystalline solid is a solid material whose constituents (such as atoms, molecules, or ions) are arranged in a highly ordered microscopic structure, forming a crystal lattice that extends in all directions. The scientific study of crystals and crystal formation is known as crystallography.

Explanation:

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A layer of sediment goes through a series of steps on its way to becoming sedimentary rock. These steps are summarized below. Re
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Explanation:

The steps involved in formation of a sedimentary rock are placed in the correct order as follows.

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As a result, it leads to the formation of a sedimentary rock.

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4 years ago
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The cell theory has three main components. Which three scientists’ conclusions formed these components?
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Matthias Schleiden, Theodor Schwann, and Rudolf Virchow.

Explanation:

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3 years ago
What is the percentage composition of cobalt in cobalt(II) fluoride, CoF2?
emmainna [20.7K]

Answer:

60.8%

Explanation:

We'll begin obtaining the molar mass of cobalt(II) fluoride, CoF2. This can be done as shown below:

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The percentage composition of cobalt in cobalt(II) fluoride, CoF2 is given by:

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=> 59/97 x 100 = 60.8%

Therefore, the percentage composition of cobalt in cobalt(II) fluoride, CoF2 is 60.8%

5 0
3 years ago
How many electrons does a Mn Mn atom have in its 3 d 3d subshell? number of electrons: 3 d electrons 3d electrons How many of th
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Answer:

[Ar] 4s² 3d⁵ or 1s² 2s² 2p⁶ 3s² 3p⁶ 4s² 3d⁵

Explanation:

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Generally electrons first enter 4s² shell filling it first before entering the 3d shell due to the lower energy 4s orbital has compared to 3d orbital. Filling of the 3d orbital must be filled parallel first before pairing begins. However in the case of manganese, it only has five electrons in its 3d orbital which will only fill it with single spins.

Due to the fact that manganese has five electrons in its 3d orbital its highly magnetic and its classified as a "ferromagnetic" substance.

Note when manganese forms a bond, it loses electrons from its 4s orbital too first to form Mn(ii) or combined from both 4s and 3d to form Mn(iii), (iv) (vi) etc.

Attached is a diagram showing how manganese atoms are arranged in its shells

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4 years ago
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