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lakkis [162]
3 years ago
9

Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq

uation H 2 S O 4 + 2 N a O H ⟶ 2 H 2 O + N a 2 S O 4 If you require 29.09 mL of 0.639 M N a O H solution to titrate 213.8 mL of H 2 S O 4 solution, what is the concentration of the H 2 S O 4 solution?
Chemistry
1 answer:
pogonyaev3 years ago
5 0

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

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Answer:

The standard cell potential is 2.00 V

Explanation:

<u>Step 1:</u> Data given

Cu is cathode because of higher EP

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<u>Step 2:</u> Balance both equations

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3*(Cu2++2e−→Cu)    E∘=0.340 V

<u>Step 3:</u> The netto equation

2 Al + 3Cu2+ +6e- → 2Al3+ + 3Cu -6e-

2 Al + 3Cu2+  → 2Al3+ + 3Cu

<u>Step 4:</u> Calculate the standard cell potential

E∘cell = E∘cathode - E∘anode

E∘cell = E∘ Cu2+/Cu - E∘ Al3+/Al

E∘cell =0.340 V - (-1.66) = 2.00 V

The standard cell potential is 2.00 V

4 0
3 years ago
One atom of silicon can properly be combined in a compound with
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<span>One atom of silicon can properly be combined in a compound with two atoms of oxygen.</span>
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Answer:

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