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lakkis [162]
2 years ago
9

Suppose you are titrating a sulfuric acid solution of unknown concentration with a sodium hydroxide solution according to the eq

uation H 2 S O 4 + 2 N a O H ⟶ 2 H 2 O + N a 2 S O 4 If you require 29.09 mL of 0.639 M N a O H solution to titrate 213.8 mL of H 2 S O 4 solution, what is the concentration of the H 2 S O 4 solution?
Chemistry
1 answer:
pogonyaev2 years ago
5 0

Answer:

Explanation:

H ₂ S O ₄ + 2 N a O H ⟶ 2 H ₂ O + N a ₂ S O ₄

29.09 mL of 0.639 M N a O H is mixed with 213.8 mL of H ₂ S O ₄

Let the concentration of H ₂ S O ₄ be S₂ .

In terms of normal or equivalent solution is will be 2 N  solution

From the formula S₁ V₁ = S₂ V₂

= 29.09 x .639 = 213.8 x  S₂

S₂ = .087 N solution

In terms of molar solution it will be .087 / 2 M

= .0435 M

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Calcium hydroxide is a strong base but is not very soluble ( Ksp = 5.02 X 10-6 ). What is the pH of a saturated solution of Ca(O
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Answer : The pH of a saturated solution is, 12.33

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Therefore, the pH of a saturated solution is, 12.33

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3 years ago
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