Answer:
0.234 M
Explanation:
C- 12.009 x 7
H- 1.001 x 5
N- 14.006
O- 16 x 3
S- 32.059
___________+
183.133 g/mol
= 0.234 M Cancel out the grams mol/L equals molarity. Lowest significant figure is 3
if you wanted to produce 8 moles of chromium IV nitrate how many moles of Lead IV nitrate would you need to use?
1 answer:
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