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Deffense [45]
3 years ago
12

1.25 cm is the same distance as ? 12.5 Km 12.5 mm 12.5 dm 12.5 m

Chemistry
1 answer:
pogonyaev3 years ago
6 0

Answer:

12.5mm

Explanation:

1cm = 10mm

so you need to multiply the 1.25 by 10 to get it in mm.

You might be interested in
A correct statement of Henry's law is: a. The concentration of a gas in solution is inversely proportional to temperature. b. Th
AVprozaik [17]

Answer:

e. None of these.

Explanation:

Hey there!

In this case, since the Henry's law is defined in terms of pressure, henry's constant and pressure, as shown below:

C=K_H*P

Whereas C is the concentration, KH the Henry's constant and P the pressure, we infer that the concentration of a gas solution is directly proportional to the pressure, which is not the group choices, therefore, the answer is e. None of these.

Best regards!

8 0
2 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
2 years ago
Help help help plsss
Olin [163]

Answer:

4.58×10^3

3.72×10^7

Explanation:

3.8×10^2 =380

+ 4.2×10^3=4200

= 4580 = 4.58×10^3

8 0
2 years ago
Plzzzzzzzzzzz helpo friend
miv72 [106K]

Answer:

They form volcanoes....

6 0
3 years ago
Calculate the mass of 12.3 moles of MgSO4.​
Afina-wow [57]

Answer:

614 034 kg

Explanation:

n = m/Mm

m = n * Mm

Mm(MgSO4) = 1 * 24.3 * 1 * 32.1 * 4 * 16 = 49921.92

m = 12.3 * 49921.92

m = 614 034 kg

8 0
2 years ago
Read 2 more answers
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