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xxMikexx [17]
3 years ago
12

HELP ASAP!!!! SCIENCE LOVERS !!! What do the lines making a circle around the LOW-PRESSURE area indicate?

Physics
2 answers:
Degger [83]3 years ago
5 0
1 is D.
2 is A.

hope i helped
brilliants [131]3 years ago
4 0

your answer is wrong

the correct answer is

1 C.

2. warm and rainy

i just took the quiz


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One cereal bar has a mass of 37 g. What is the mass of 6 cereal bars? Is that more than or less than 1 kg? Explain your answer.
GuDViN [60]

The mass is 222g.  No, it is less than 1kg.  There are 1000 grams in a kilogram so it would be 0.222kg.  Hope this Helps :D

7 0
3 years ago
How many animals lost each hour
joja [24]

Answer:

562

Explanation:

6 0
3 years ago
Electronic flash units for camera contain a capacitor for storing the energy used to produce the flash. In one such unit, the fl
nadezda [96]

Answer:

420J

Explanation:

Power is the time rate of change in energy. Power is the ratio of energy to time. The S.I unit of power is in watts.

Given that the flash lasts for 1/675 s, power output is 2.7 * 10⁵ W. Hence:

Power = Energy / time

Substituting:

2.7 * 10⁵ W = Energy / (1/675)

Energy = 2.7 * 10⁵ W * 1/675 = 400J

Therefore the energy emitted as light is 400J.

Since the conversion of electric energy to light is 95% efficient, hence the energy stored as electrical energy is:

Energy(capacitor) = 5% of 400J + 400J = 0.05*400 + 400

Energy(capacitor) = 420J

8 0
3 years ago
An infant's toy has a 120 g wooden animal hanging from a spring. If pulled down gently, the animal oscillates up and down with a
Morgarella [4.7K]

Answer:

0.37 m

Explanation:

The angular frequency, ω, of a loaded spring is related to the period, T,  by

\omega = \dfrac{2\pi}{T}

The maximum velocity of the oscillation occurs at the equilibrium point and is given by

v = \omega A

A is the amplitude or maximum displacement from the equilibrium.

v = \dfrac{2\pi A}{T}

From the the question, T = 0.58 and A = 25 cm = 0.25 m. Taking π as 3.142,

v = \dfrac{2\times3.142\times0.25\text{ m}}{0.58\text{ s}} = 2.71 \text{ m/s}

To determine the height we reached, we consider the beginning of the vertical motion as the equilibrium point with velocity, v. Since it is against gravity, acceleration of gravity is negative. At maximum height, the final velocity is 0 m/s. We use the equation

v_f^2 = v_i^2+2ah

v_f is the final velocity, v_i is the initial velocity (same as v above), a is acceleration of gravity and h is the height.

h = \dfrac{v_f^2 - v_i^2}{2a}

h = \dfrac{0^2 - 2.71^2}{2\times-9.81} = 0.37 \text{ m}

3 0
3 years ago
A compact car has a maximum acceleration of 2.0 m/s2 when it carries only the driver and has a total mass of 1100 kg . you may w
nadya68 [22]

According to Newton`s  law. Force exerted by car,

F = m a = 1100 kg \times 2 m/s^2 = 2200 \ N

After adding an additional 400 kg of mass, the force will be same therefore the acceleration

F = 2200 \ N = (1100 \ kg + 400 \ kg)  a \\\\ a = \frac{2200 \ N}{1500 \ kg} = 1.47 \ m/s^2

Thus, the acceleration after adding the masses is 1.47 \ m/s^2.

4 0
3 years ago
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