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Eva8 [605]
3 years ago
11

Suppose you pour water into a container until it reaches a depth of 21 cm. next, you carefully pour in a 11-cm thickness of oliv

e oil so that it floats on top of the water. what is the pressure at the bottom of the container? (express your answer to four significant digits.)
Physics
1 answer:
ipn [44]3 years ago
8 0
<span>3040. Pascals. The density of olive oil is 0.911 g/cm^3 and the density of water is 1.000 g/cm^3. To calculate the pressure of 1 cm of water, 1000 kg/m^3 * 9.8 m/s^2 * 0.01 m = 98.000 Pa To calculate the pressure of 1 cm of olive oil 911 kg/m^3 * 9.8 m/s^2 * 0.01 m = 89.278 Pa Now to calculate the pressure at the bottom of the container, simply add the products of how many cm of each fluid you have. So 21 * 98.000 Pa + 11 * 89.278 Pa = 2058 Pa + 982.058 Pa = 3040.058 Pa So the pressure at the bottom of the container will be 3040. Pascals.</span>
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The percentage of mechanical energy of the oscillator lost in each cycle is 5.91 %.

The formula for mechanical energy in an oscillator is given by

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It is the sum of elastic potential energy and kinetic energy.

Amplitude is nothing but the maximum displacement moved by a point on vibrating body.

It is given that the amplitude A decreases by 3%, then

(E₂ - E₁) / E₁ = [1/2 k (A₂²- A₁²)] /(1/2 k A₁²) = (A₂²- A₁²)/ A₁² = (97² - 100²)/ 100²

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To know more about mechanical energy:

brainly.com/question/4285515

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E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

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E=2K\lambda d\dfrac{L }{d^2\sqrt{L^2+d^2}}

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