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Eva8 [605]
2 years ago
11

Suppose you pour water into a container until it reaches a depth of 21 cm. next, you carefully pour in a 11-cm thickness of oliv

e oil so that it floats on top of the water. what is the pressure at the bottom of the container? (express your answer to four significant digits.)
Physics
1 answer:
ipn [44]2 years ago
8 0
<span>3040. Pascals. The density of olive oil is 0.911 g/cm^3 and the density of water is 1.000 g/cm^3. To calculate the pressure of 1 cm of water, 1000 kg/m^3 * 9.8 m/s^2 * 0.01 m = 98.000 Pa To calculate the pressure of 1 cm of olive oil 911 kg/m^3 * 9.8 m/s^2 * 0.01 m = 89.278 Pa Now to calculate the pressure at the bottom of the container, simply add the products of how many cm of each fluid you have. So 21 * 98.000 Pa + 11 * 89.278 Pa = 2058 Pa + 982.058 Pa = 3040.058 Pa So the pressure at the bottom of the container will be 3040. Pascals.</span>
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Joseph's experiment could be improved by using the same antenna at each part of the house during each trial instead of using different antenna. By doing so, he can obtain accurate results how is the signal in different part of the house under the same conditions (despite the location). So, he will see the dependence of the signal on the location. If he uses different antenna, than this antenna can also have influence of the signal.
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3 years ago
A force of 10 N acts on an object with a mass of 10 kg. What is its acceleration? A. 1 m/s2 B. 10 m/s2 C. 2 m/s2 D. 5 m/s2
Akimi4 [234]

The acceleration exerted by the object of mass 10 kg is \mathbf{1} m / \boldsymbol{s}^{2}

Answer: Option A

<u>Explanation:</u>

According to Newton’s second law of motion, any external force acting on a body will be directly proportional to the mass of the body as well as acceleration exerted by the body. So, the net external force acting on any object will be equal to the product of mass of the object with acceleration exerted by the object. Thus,

                  Force = Mass \times Acceleration

So,

                 Acceleration=\frac{\text {Force}}{\text {Mass}}

As the force acting on the object is stated as 10 N and the mass of the object is given as 10 kg, then the acceleration will be

                  Acceleration =\frac{10 \mathrm{N}}{10 \mathrm{kg}}=1 \mathrm{m} / \mathrm{s}^{2}

So, the acceleration exerted by the object of mass 10 kg is \mathbf{1} m / \boldsymbol{s}^{2}

4 0
3 years ago
A bicycle tire of a radius of 0.44 m has a piece of gum stuck on its rim. What is the angle through which the tire rotates when
Karolina [17]

Based on the calculations, the angle through which the tire rotates is equal to 4.26 radians and 244.0 degrees.

<h3>How to calculate the angle?</h3>

In Physics, the distance covered by an object in circular motion can be calculated by using this formula:

S = rθ

<u>Where:</u>

  • r is the radius of a circular path.
  • θ is the angle measured in radians.
  • S is the distance.

Substituting the given parameters into the formula, we have;

1.87 = 0.44 × θ

θ = 1.87/0.44

θ = 4.26 radians.

Next, we would convert this value in radians to degrees:

θ = 4.26 × 180/π

θ = 4.26 × 180/3.142

θ = 244.0 degrees.

Read more on radians here: brainly.com/question/19758686

#SPJ1

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1 year ago
Dense water near the poles sinks, creating a current towards the equator. What would you expect to happen to this current if tem
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3 years ago
Suppose a rocket ship in deep space moves with constant acceleration equal to 9.80 m/s2, which gives the illusion of normal grav
DochEvi [55]

Answer:

a) 3673469.39 seconds

b) 6.61×10¹⁴ m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity = 0.12×3×10⁸ m/s

s = Displacement

a = Acceleration due to gravity = 9.8 m/s²

Equation of motion

v=u+at\\\Rightarrow 0.12\times 3\times 10^8=0+9.8t\\\Rightarrow t=\frac{0.12\times 3\times 10^8}{9.8}=3673469.39\ s

Time taken to reach 12% of light speed is 3673469.39 seconds

v^2-u^2=2as\\\Rightarrow s=\frac{v^2-u^2}{2a}\\\Rightarrow s=\frac{(0.12\times 3\times 10^8)^2-0^2}{2\times 9.8}\\\Rightarrow s=6.61 \times 10^{14}\ m

The distance it would have to travel is 6.61×10¹⁴ m

7 0
3 years ago
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