The percentage of mechanical energy of the oscillator lost in each cycle is 5.91 %.
The formula for mechanical energy in an oscillator is given by
E = 1/2 kA²
It is the sum of elastic potential energy and kinetic energy.
Amplitude is nothing but the maximum displacement moved by a point on vibrating body.
It is given that the amplitude A decreases by 3%, then
(E₂ - E₁) / E₁ = [1/2 k (A₂²- A₁²)] /(1/2 k A₁²) = (A₂²- A₁²)/ A₁² = (97² - 100²)/ 100²
⇒ 5.91% of the mechanical energy is lost in each cycle.
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UP gaining potential
Down Gaining Kinetic
The answer is B. It is measured in amperes.
Answer:

Explanation:
Given that
Length= 2L
Linear charge density=λ
Distance= d
K=1/(4πε)
The electric field at point P



So

Now by integrating above equation

==> Infrared waves from the sun, green light from the sun, and X-rays from the sun, all travel through vacuum.
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