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Gnom [1K]
4 years ago
9

In which medium does sound travel the fastest?

Physics
2 answers:
TEA [102]4 years ago
7 0

Sound travels through solids the fastest

Hope it helps...

topjm [15]4 years ago
4 0

sound travels faster through solid objects because a solid objects particles are packed together so the sound particles can bump with them easily to create sound. in air it needs to find a particle to bump with which is much more harder but with a solid its easier.

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Is there a way to see the color of cosmic rays the human eye can't see
KATRIN_1 [288]
You would have to use a machine to convert the colors to one visible by humans or become some other species of animal with a larger light spectrum.
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3 years ago
If you are an astronaut in the middle of the near side of the moon during a full moon,how would the ground around you look?How w
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3 0
3 years ago
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After a projectile is fired into the air, what is the acceleration in the x-direction? (Assume no air resistance.)
Gre4nikov [31]
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3 years ago
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What traits did Sir William Gilbert have that made him a good scientist?
11111nata11111 [884]
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4 0
3 years ago
Light of wavelength 550 nm falls on a
Brums [2.3K]

Answer:

The first diffraction maximum fringe will be at approximately 2.7 meters from the central maximum.

Explanation:

We can describe single slit diffraction phenomenon with the equation:

a\sin\theta=m\lambda (1)

with θ the angular position of the minimum of order m respect the central maximum, a the slit width and λ the wavelength of the incident light. Because the distances between the first minima and the central maximum (y_{m}) are small compared to the distance between the screen and the slit (x), we can approximate \sin\theta\approx\tan\theta=\frac{y}{x}, using this on (1):

a\frac{y_{m}}{x}=m\lambda

solving for y

y_{m}= \frac{mx\lambda}{a}

Note that y_{m}is the distance between a minimum and the central maximum but we need the position of a maximum not a minimum, here we can use the fact that a maximum is approximately between two minima, so the first diffraction maximum fringe is between the minima of order 1 and 2, so we should find y_{1}, y_{2} add them and divide by two:

y_{1}= \frac{(1)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}

y_{1}= 1.8 m

y_{2}= \frac{(2)(10.0m)(550\times10^{-9}\,m)}{3.00\times10^{-6}\,m}

y_{1}= 3.6 m

maximum = \frac{1.8+3.6}{2}=2.7m

7 0
3 years ago
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