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aleksandrvk [35]
3 years ago
6

Will a double replacement reaction occur if a potassium hydroxide solution is mixed with a lead(II) nitrate solution? Briefly ex

plain.
Chemistry
2 answers:
jonny [76]3 years ago
4 0

Explanation:

A chemical reaction equation that contains same number of atoms on both reactant and product side is known as a balanced chemical reaction equation.

And, when positive and negative ions of the two reactant species exchange their position then this type of reaction is known as double replacement reaction.

For example, KOH + Pb(NO_{3})_{2} \rightarrow KNO_{3} + Pb(OH)_{2}

Here, number of reactant molecules are as follows.

K = 1

OH = 1

Pb = 1

NO_{3} = 2

Number of product molecules are as follows.

K = 1

OH = 2

Pb = 1

NO_{3} = 1

Hence, to balance this equation multiply KOH by 2 on reactant side and multiply KNO_{3} by 2 on product side.

Therefore, the balanced chemical reaction equation is as follows.

      2KOH + Pb(NO_{3})_{2} \rightarrow 2KNO_{3} + Pb(OH)_{2}

Since, both positive and negative ions on the reactant side get exchanged. Hence, it is a double replacement reaction.

ohaa [14]3 years ago
3 0
No - a precipitation will occur though. Potassium nitrate is soluble in water, so the potassium and nitrate ions will remain spectator ions and stay in solution. Lead (II) hydroxide is not soluble, and will precipitate out of solution to form a solid product.
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Calculate the percent of each component in the mixture. Show your calculations. Circle final answers.
Colt1911 [192]

Answer:

See Explanation

Explanation:

The question is incomplete; as the mixtures are not given.

However, I'll give a general explanation on how to go about it and I'll also give an example.

The percentage of a component in a mixture is calculated as:

\%C_E = \frac{E}{T} * 100\%

Where

E = Amount of element/component

T = Amount of all elements/components

Take for instance:

In (Ca(OH)_2)

The amount of all elements is: (i.e formula mass of (Ca(OH)_2))

T = 1 * Ca + 2 * H + 2 * O

T = 1 * 40 + 2 * 1 + 2 * 16

T = 74

The amount of calcium is: (i.e formula mass of calcium)

E = 1 * Ca

E = 1 * 40

E = 40

So, the percentage component of calcium is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{40}{74} * 100\%

\%C_E = \frac{4000}{74}\%

\%C_E = 54.05\%

The amount of hydrogen is:

E = 2 * H

E = 2 * 1

E = 2

So, the percentage component of hydrogen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{2}{74} * 100\%

\%C_E = \frac{200}{74}\%

\%C_E = 2.70\%

Similarly, for oxygen:

The amount of oxygen is:

E = 2 * O

E = 2 * 16

E = 32

So, the percentage component of oxygen is:

\%C_E = \frac{E}{T} * 100\%

\%C_E = \frac{32}{74} * 100\%

\%C_E = \frac{3200}{74}\%

\%C_E = 43.24\%

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Answer: im thinking its gonna be d.C2H6 and also

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Explanation:

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