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iragen [17]
3 years ago
6

Q15. Natural gas burns in air to form carbon dioxide and water to releasing heat. CHA(g) O2 (g) CO2 g) H20 (g) AH 802.3 kJ What

minimum mass of CH4 is required to heat 55 g of water by 25 °C? (Assume 100% heating efficiency. c) 115 g a) 0.115 g b) 2.25 x 103 g d) 8.70 g
Chemistry
1 answer:
mestny [16]3 years ago
6 0

Answer:

a) 0.115 g

Explanation:

The balanced reaction is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

To heat 55g of water, the energy in form of heat necessary can be calculated by:

Q = mcΔT

where Q is the heat, m is the mass, c is the specific heat (for water, c = 4.18 J/gºC), and ΔT is the variation of the temperature, which is 25ºC, so:

Q = 55x4.18x25

Q = 5747.5 J = 5.7475 kJ

So, for the reaction, 1 mol of CH₄ releases 802.3 kJ, so to release 5.7475 kJ will be necessary:

1 mol ---------------- 802.3 kJ

x ---------------- 5.7475 kJ

By a simple direct three rule:

802.3x = 5.7475

x = 7.164x10⁻³mol

The molar mass of CH₄ is : 12 (of C) + 4x1 (of H) = 16 g/mol

The mass is equal to the number of moles multiplied by molar mass, the:

m = 7.164x10⁻³x16

m = 0.115 g

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motikmotik

Answer: If the Sun had an even greater mass then it currently does, it would have a larger gravitational pull and since it's heat would be closer to Earth, both by magnitude and gravity, life on Earth wouldn't be possible and life on Mars would be reality. Also, when the sun would explode, it would have a larger supernova and possibly create a white dwarf (something that only happens to red supergiant stars when they die), with a gravitational force so strong it wold have two beams of light coming out it's north and south poles (like a black hole).

I hope this helps!

7 0
3 years ago
A company's managers ask, "Should we increase the size of our Bluetooth wireless speaker and sell it at a higher cost?" Never pr
Ivahew [28]

Complete Question

Identify whether the following activity on the table shown on the first uploaded image are examples of business level or  corporate level strategy

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Explanation:

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5 0
3 years ago
Rxn
givi [52]

Answer: The enthalpy of formation of SO_3 is  -396 kJ/mol

Explanation:

Calculating the enthalpy of formation of SO_3

The chemical equation for the combustion of propane follows:

2SO_2(g)+O_2(g)\rightarrow 2SO_3(g)

The equation for the enthalpy change of the above reaction is:

\Delta H^o_{rxn}=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta H^o_f_{(SO_2(g))})+(1\times \Delta H^o_f_{(O_2(g))})]

We are given:

\Delta H^o_f_{(O_2(g))}=0kJ/mol\\\Delta H^o_f_{(SO_2(g))}=-297kJ/mol\\\Delta H^o_{rxn}=-198kJ

Putting values in above equation, we get:

-198=[(2\times \Delta H^o_f_{(SO_3(g))})]-[(2\times \Delta -297)+(1\times (0))]\\\\\Delta H^o_f_{(SO_3(g))}=-396kJ/mol

The enthalpy of formation of SO_3 is -396 kJ/mol

4 0
3 years ago
Unknown element has two isotopes. Isotope A has a mass of 34 amu and abundance of 52%, isotope B has a mass of 33 amu and abunda
ZanzabumX [31]

Answer:

x = 33.52 amu

Explanation:

It is given that,

Isotope A has a mass of 34 amu and an abundance of 52%, isotope B has a mass of 33 amu and an abundance of 48%.

Let x is the average atomic mass of this element. It can be calculated as follows :

x=52\%\ \text{of}\ 34+48\%\ \text{of}\ 33\\\\x=\dfrac{52}{100}\times 34+\dfrac{48}{100}\times 33\\\\x=0.52\times 34+0.48\times 33\\\\x=33.52\ \text{amu}

So, the average atomic mass of this element is 33.52 amu.

4 0
3 years ago
What is the pH of a solution of H2SO4 that has [H3O+] = 5.45 × 10–5 M?
Katena32 [7]
In chemistry, pH<span> is a numeric scale used to specify the acidity or basicity of an aqueous solution. It is approximately the negative of the base 10 logarithm of the concentration of hydronium ions. We calculate as follows:

pH = -log [H3O+]
pH = -log[</span><span>5.45 × 10–5 M]
pH = 4.3</span>
5 0
3 years ago
Read 2 more answers
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