1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
iragen [17]
3 years ago
6

Q15. Natural gas burns in air to form carbon dioxide and water to releasing heat. CHA(g) O2 (g) CO2 g) H20 (g) AH 802.3 kJ What

minimum mass of CH4 is required to heat 55 g of water by 25 °C? (Assume 100% heating efficiency. c) 115 g a) 0.115 g b) 2.25 x 103 g d) 8.70 g
Chemistry
1 answer:
mestny [16]3 years ago
6 0

Answer:

a) 0.115 g

Explanation:

The balanced reaction is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

To heat 55g of water, the energy in form of heat necessary can be calculated by:

Q = mcΔT

where Q is the heat, m is the mass, c is the specific heat (for water, c = 4.18 J/gºC), and ΔT is the variation of the temperature, which is 25ºC, so:

Q = 55x4.18x25

Q = 5747.5 J = 5.7475 kJ

So, for the reaction, 1 mol of CH₄ releases 802.3 kJ, so to release 5.7475 kJ will be necessary:

1 mol ---------------- 802.3 kJ

x ---------------- 5.7475 kJ

By a simple direct three rule:

802.3x = 5.7475

x = 7.164x10⁻³mol

The molar mass of CH₄ is : 12 (of C) + 4x1 (of H) = 16 g/mol

The mass is equal to the number of moles multiplied by molar mass, the:

m = 7.164x10⁻³x16

m = 0.115 g

You might be interested in
What is the reducing agent in the reaction below?
trapecia [35]
Al    is  the  reducing  agent.That    is  answer  B  is  the  above  answer
  Al  acts  as  a  strong  reducing  agent.  It  reduces  crO3  to  form cr  while  Al  is  oxidized  to  Al2O3.    Al is  capable  to  reduce  cr  since  Al  is  higher  in   reactivity  series  than  cr.
8 0
3 years ago
Determine the molar masses for each of the following elements, compounds, or molecules. Remember to round to the proper amount o
ra1l [238]

Answer:

Explanation:

Cu(OH)2 _97.65 g/mol

Na2WO4 _293.82 g/mol

Pd _106.42 g/mol

KMnO4 _158.03 g/mol

NH3 _17.03 g/mol

3 0
2 years ago
Read 2 more answers
Which of the following metals is in a liquid state at room temperature?
SpyIntel [72]
The answer is c. hg (mercury)
5 0
3 years ago
The law of conservation of matter states that matter can be neither created nor destroyed. Your friend shows you the following c
WITCHER [35]

Answer:

According to conservation of matter, there should be equal amounts of all elements on both the reactant and product side.

Reactant:

1 Ca

1 C

1 O

Product:

1 Ca

1 C

3 O

Therefore, your friend is right because the law of conservation of matter is not followed in this chemical equation.

Explanation:

6 0
2 years ago
What is the total number of joules required to freeze a 10 g sample of water at 0°C?
Lunna [17]

Explanation:

the answer will be 98.4 kJ

8 0
3 years ago
Other questions:
  • How many moles of calcium chloride (CaCl2) are needed to react completely with 6.2 moles of silver nitrate (AgNO3)? 2AgNO3 + CaC
    15·1 answer
  • Which conversion factor should you use first to calculate the number of grams of co2 produced by the reaction of 50.6 g of ch4 w
    15·1 answer
  • 1.42 mol sample of neon gas at a temperature of 13.0 °C is found to occupy a volume of 25.5 liters. The pressure of this gas sam
    9·1 answer
  • Make a circle graph for each set of data. Top 5 Most Linked-To Sites on the World Wide Web Site Hits (millions) America Online (
    7·1 answer
  • Organelle where energy is released from<br>broken-down food molecules​
    13·1 answer
  • Which shows the conversion of 8.93 × 10-2 grams to milligrams?
    9·1 answer
  • To evaluate R. the volume of a gas measured in the temperature of the gas is measured in<br> while
    9·2 answers
  • Which of the following is least likely to change the gene pool of a population of chipmunks?
    12·1 answer
  • Someone please answer
    9·1 answer
  • What are the common properties of the following element groups:
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!