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iragen [17]
3 years ago
6

Q15. Natural gas burns in air to form carbon dioxide and water to releasing heat. CHA(g) O2 (g) CO2 g) H20 (g) AH 802.3 kJ What

minimum mass of CH4 is required to heat 55 g of water by 25 °C? (Assume 100% heating efficiency. c) 115 g a) 0.115 g b) 2.25 x 103 g d) 8.70 g
Chemistry
1 answer:
mestny [16]3 years ago
6 0

Answer:

a) 0.115 g

Explanation:

The balanced reaction is:

CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

To heat 55g of water, the energy in form of heat necessary can be calculated by:

Q = mcΔT

where Q is the heat, m is the mass, c is the specific heat (for water, c = 4.18 J/gºC), and ΔT is the variation of the temperature, which is 25ºC, so:

Q = 55x4.18x25

Q = 5747.5 J = 5.7475 kJ

So, for the reaction, 1 mol of CH₄ releases 802.3 kJ, so to release 5.7475 kJ will be necessary:

1 mol ---------------- 802.3 kJ

x ---------------- 5.7475 kJ

By a simple direct three rule:

802.3x = 5.7475

x = 7.164x10⁻³mol

The molar mass of CH₄ is : 12 (of C) + 4x1 (of H) = 16 g/mol

The mass is equal to the number of moles multiplied by molar mass, the:

m = 7.164x10⁻³x16

m = 0.115 g

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Data:
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Solving:

\frac{3}{100}*147.71 =  \frac{443.13}{100} \approx \boxed{4.43\:pounds\:of\:body\:fat}\end{array}}\qquad\quad\checkmark


8 0
3 years ago
What layer is made of metals and is a solid?<br> A.Mesosphere<br> B.inner core<br> C.outer core
Nookie1986 [14]
B because inner core has metal and it’s solid
7 0
3 years ago
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JUST ONE MULTIPLE CHOICE QUESTION!
Butoxors [25]
I think it’s The second option sorry if I’m wrong
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3 years ago
How many moles of methane (CH4) could be made from 4.6 moles of hydrogen?
DENIUS [597]

Answer:

Number of moles of methane form = 2.3 mol

Explanation:

Given data:

Number of moles of Hydrogen = 4.6 mol

Number of moles of methane form = ?

Solution:

Chemical equation:

C + 2H₂     →   CH₄

Now we will compare the moles of methane with hydrogen from balance chemical equation.

                     H₂              :           CH₄

                       2              :             1

                     4.6             :            1/2×4.6 = 2.3 mol  

Form 3.6 moles of hydrogen 2.3 moles of methane can be formed.

6 0
3 years ago
The decomposition of N2O to N2 and O2 is a first-order reaction. At 730°C, the rate constant of the reaction is 1.94 × 10-4 min-
grin007 [14]

Answer:

Total pressure 5.875 atm

Explanation:

The equation for above decomposition is

2N_2O \rightarrow 2N_2 + O_2

rate constant k =  1.94\times 10^{-4} min^{-1}

Half life t_{1/2} = \frac{0.693}{k} = 3572 min

Initial pressure N_2 O = 4.70 atm

Pressure after 3572 min = P

According to first order kinematics

k = \frac{1}{t} ln\frac{4.70}{P}

1.94\times 10^{-4} = \frac{1}{3572} \frac{4.70}{P}

solving for P we get

P = 2.35 atm

2N_2O \rightarrow 2N_2 + O_2

initial           4.70                         0             0

change        -2x                          +2x           +x

final             4.70 -2x                     2x           x

pressure ofO_2 after first half life  = 2.35 = 4.70 - 2x

                                                          x = 1.175

pressure of N_2 after first half life  =  2x = 2(1.175) = 2.35 ATM

Total pressure  = 2.35 + 2.35 + 1.175

                          = 5.875 atm

5 0
3 years ago
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