Answer:
Specific heat of water = 33.89 KJ
Explanation:
Given:
mass of water = 81 gram
Initial temperature = 0°C
Final temperature = 100°C
Specific heat of water = 4.184
Find:
Required heat Q
Computation:
Q = Mass x Specific heat of water x (Final temperature - Initial temperature)
Q = (81)(4.184)(100-0)
Q = 33,890.4
Specific heat of water = 33.89 KJ
<u><em>Answer: Chemical reaction, a process in which one or more substances, the reactants, are converted to one or more different substances, the products.</em></u>
Explanation:
Answer:
The minimum rate of fresh air in the room is 176 moles/min
Explanation:
High exposure of CO₂ has health effects as headaches, increased heart rate, elevated blood pressure, coma, asphyxia, convulsions, etc.
0,500 mole% of CO₂ in air means 0,500 moles of CO₂ per 100 moles of air
As the rate of sublimation of CO₂ is 0,880, the minimum rate of fresh air in the room must be:
X = <em>176 moles of Air/min</em>
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I hope it helps!