Answer:
Rate = -1/2 Δ[SO<sub>2</sub>]/Δt
so its gonna be (in more simple terms) rate= -1/2Δ(SO2)/Δt
Explanation:
The reaction between hydrogen and oxygen to form water is given as:
![H_2 + O_2 \rightarrow H_2O](https://tex.z-dn.net/?f=H_2%20%2B%20O_2%20%5Crightarrow%20H_2O)
The balanced reaction is:
![2H_2 + O_2 \rightarrow 2H_2O](https://tex.z-dn.net/?f=2H_2%20%2B%20O_2%20%5Crightarrow%202H_2O)
According to the balanced reaction,
4 g of hydrogen (
) reacts with 32 g of oxygen (
).
So, oxygen reacted with 29.4 g of hydrogen is:
![\frac{29.4\times 32}{4} = 235.2 g](https://tex.z-dn.net/?f=%5Cfrac%7B29.4%5Ctimes%2032%7D%7B4%7D%20%3D%20235.2%20g)
Hence, the mass of oxygen that is reacted with 29.4 g of hydrogen is 235.2 g.
I think B. As an idea is just a way that could be possible