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kvasek [131]
3 years ago
5

Pretend that you are the size of an atom, observing a reaction between a potassium atom and a fluorine atom. Write an account of

the formation of an ionic bond as the atoms react. Tell what happens to the valence electrons on each atom and how each atom is changed by losing or gaining electrons.
Chemistry
1 answer:
natka813 [3]3 years ago
3 0
Potassium will loss it's electron because it have a character of electropositively therefore it's electron will transfer to flouren which will make stable and complete of it's electro configuration. Now potassium will have negative charge due to loss it's outer most electron on it's orbit and flourine will take negatively charge too because of complete it's outer most shell to be completed.(But we have to know that at first flourine was had a positive charge because of not completed of it's outer most shell)
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Analyzing a specific reaction Consider the following reaction: 2Mg+O2→2MgO,rate=k[Mg][O2]2 Part A What is the overall reaction o
stepladder [879]

Answer:

3

Explanation:

Order of in the mass action law is the coefficient which is raised to the active concentration of the reactants. It is experimentally determined and can be zero, positive negative or fractional.

The order of the whole reaction is the sum of the order of each reactant which is raised to its power in the rate law.

Thus,

For the reaction:-

2Mg+O₂→2MgO

Rate  = k[Mg][O₂]²

Order w.r.t. Mg = 1

Order w.r.t. O₂ = 2

<u>So, order of the overall reaction = 1 + 2 = 3</u>

7 0
3 years ago
0.000068 g Express your answer as an integer.
ivann1987 [24]
6.8x10^5? Scientific notation
5 0
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sattari [20]
Boyle’s law gives the relationship between pressure and volume of gases. It states that at constant temperature the pressure of gas is inversely proportional to volume of gas.
PV = k
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P1V1 = P2V2
Parameters at STP are on the left side and parameters for the second instance are on the right side of the equation
P1 - standard pressure - 1.0 atm
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5 0
3 years ago
Human reaction time is usually about 0.18 s. If your lab partner holds a ruler between your finger and thumb and releases it fro
Marizza181 [45]

Answer:

–0.16 m

Explanation:

From the question given above, the following data were obtained:

Time (t) = 0.18 s

Acceleration due to gravity (g) = –9.81 m/s²

Height (h) =?

We can obtain how far the ruler will fall by using the following equation:

H = ½gt²

H = ½ × –9.81 × 0.18²

H = ½ × –9.81 × 0.0324

H = –0.16 m

Thus, the ruler will fall –0.16 m before you will catch it.

7 0
3 years ago
Answer the following for the reaction: 3AgNO3(aq)+Na3PO4(aq)→Ag3PO4(s)+3NaNO3(aq)
Brums [2.3K]

Answer:1) Volume of AgNO_3 required is 55.98 mL.

2) 0.62577 grams of Ag_3PO_4 is produced.

Explanation:

3AgNO_3(aq)+Na_3PO_4(aq)\rightarrow Ag_3PO_4(s)+3NaNO_3(aq)

1) Molarity of AgNO_3,M_1=0.225 M

Volume of AgNO_3.V_1=?

Molarity of Na_3PO_4,M_2=0.135 M

Volume of Na_3PO_4,V_2=31.1 mL=0.0311 L

Molarity=\frac{\text{number of moles}}{\text{volume of solution in liters}}

\text{number of moles }Na_3PO_4=M_2\times V_2=0.135 mol/L\times 0.0311 L=0.0041985 moles

According to reaction, 1 mole of Na_3PO_4 reacts with 3 mole of AgNO_3, then, 0.0041985 moles of Na_3PO_4 will react with:

\frac{3}{1}\times 0.0041985 moles of AgNO_3 that is 0.0125955 moles.

M_1=0.225 M=\frac{\text{number of moles of }AgNO_3}{V_1}

V_1=\frac{0.0125955 moles}{0.225 M}=0.05598 L=55.98 mL

Volume of AgNO_3 required is 55.98 mL.

2)

Molarity=0.195 M=\frac{\text{number of moles}}{\text{volume of solution in liters}}

Number of moles of AgNO_3=0.195\times 0.023 L=0.004485 moles

According to reaction, 3 moles of AgNO_3 gives 1 mole of Ag_3PO_4, then 0.004485 moles of AgNO_3 will give:\frac{1}{3}\times 0.004485 moles of Ag_3PO_4 that is 0.001495 moles.

Mass of Ag_3PO_4 =

Moles of Ag_3PO_4 × Molar Mass of Ag_3PO_4

= 0.001495 moles × 418.58 g/mol = 0.62577 g

0.62577 grams of Ag_3PO_4 is produced.

7 0
4 years ago
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