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Minchanka [31]
3 years ago
14

Could u plz help I don't know this at all

Mathematics
1 answer:
Papessa [141]3 years ago
7 0

The area of the given figure is 56 sq cm

Step-by-step explanation:

Given,

The figure consists of 5 different diagrams: 4 triangles and a square

Each side of square = 4 cm

Height(h) of the triangle = 5 cm

Base(b) of the triangle = 4 cm

To find the area of the given figure

Formula

Area of square = side × side sq cm

Area of triangle = \frac{1}{2}×base × height

So, area of square = 4 ×4 sq cm = 16 sq cm

Area of triangle = \frac{1}{2}×4×5 sq cm = 10 sq cm

The area of 4 triangles = 10×4 sq cm = 40 sq cm

Hence the area of the given diagram = 40 + 16 sq cm = 56 sq cm

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If f(x) = 2x^3 - 14x^2 + 38x -26 and x-1 is a factor of f(x) find all of the zeros of f(x) algebraically.
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Step-by-step explanation:

First confirm that x = 1 is one of the zeros.

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=========================

next perform a long division

x -1  || 2x^3 - 14x^2 + 38x - 26 || 2x^2 - 12x + 26

          2x^3 - 2x^2

          ===========

                    -12x^2 + 28x

                     -12x^2 +12x

                     ==========

                                  26x -26

                                  26x - 26

                                 ========

                                      0

Now you can factor 2x^2 - 12x + 26

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So you are going to get a complex result.

x = -(-6) +/- sqrt(-16)

     =============

                 2

x  = 3 +/- 2i

f(x) = 2*(x - 1)*(x - 3 + 2i)*(x - 3 - 2i)

The zeros are

1

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