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Arisa [49]
3 years ago
10

Assume that temperature and number of moles of gas are constant in this problem.

Chemistry
1 answer:
IrinaVladis [17]3 years ago
4 0

Question:

a. a direct linear relationship

b. an inverse linear relationship

c. a direct nonlinear relationship

d. an inverse nonlinear relationship

Answer:

The correct option is;

d. An inverse nonlinear relationship

Explanation:

From the universal gas equation, we have;

P·V = n·R·T

Where we have the temperature, T and the number of moles, n constant, therefore, we have

P×V = Constant, because, R, the universal gas constant is also constant, hence;

P×V = C

P = \frac{C}{V}

Since P varies with V then the graphical relationship will be an inverse nonlinear as we have

V P    C

1 5         5

2 2.5      5

3 1.67     5

4 1.25     5

5 1          5

6 0.83    5

7 0.7      5

8 0.63    5

9 0.56    5

10 0.5      5

Where:

V = Volume

P = Pressure

C = Constant = 5

P = C/V

The graph is attached.

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The answer is D it was on Brainly
8 0
2 years ago
A 62.6-gram piece of heated limestone is placed into 75.0 grams of water at 23.1°C. The limestone and the water come to a final
alekssr [168]

Answer:

208.7°C was the initial temperature of the limestone.

Explanation:

Heat lost by limestone will be equal to heat gained by the water

-Q_1=Q_2

Mass of limestone = m_1=62.6 g

Specific heat capacity of limestone = c_1=0.921 J/g^oC

Initial temperature of the limestone = T_1=?

Final temperature = T_2=T =  51.9°C

Q_1=m_1c_1\times (T-T_1)

Mass of water= m_2=75.0 g

Specific heat capacity of water= c_2=4.186 J/g^oC

Initial temperature of the water = T_3=23.1^oC

Final temperature of water = T_2=T =  51.9°C

Q_2=m_2c_2\times (T-T_3)

-Q_1=Q_2

-(m_1c_1\times (T-T_1))=m_2c_2\times (T-T_3)

On substituting all values:

-(62.6 g\times 0.921 J/g^oC\times (51.9^oC-T_1))=75.0 g\times 4.186 J/g^oC\times (51.9^oC-23.1^oC)

T_1=208.7^oC

208.7°C was the initial temperature of the limestone.

7 0
3 years ago
Please answer this please don't answer if you don't know it thank you D.<br>look at the picture​
Lina20 [59]

Answer:

B.

Explanation:

The complementary strand always has the opposite base that connects for example; the opposite of A is T.

3 0
3 years ago
Calculate the number of water (H2O) molecules produced from the decomposition of 75.50 grams of Iron (III) hydroxide (Fe(OH)3).
Phantasy [73]

Answer: 6.38\times 10^{23} molecules of water are produced.

Explanation:

To calculate the moles :

\text{Moles of solute}=\frac{\text{given mass}}{\text{Molar Mass}}    

\text{Moles of} Fe(OH)_3=\frac{75.50g}{106.8g/mol}=0.707moles

The balanced chemical reaction is:

2Fe(OH)_3\rightarrow Fe_2O_3+3H_2O  

According to stoichiometry :

2 moles of Fe_2O_3 produce = 3 moles of H_2O

Thus 0.707 moles of Fe_2O_3 will produce=\frac{3}{2}\times 0.707=1.06moles  of H_2O  

According to avogadro's law, 1 mole of every substance contains avogadro's number 6.023\times 10^{23} of particles.

Thus 1.06 moles of H_2O contains = \frac{6.023\times 10^{23}}{1}\times 1.06=6.38\times 10^{23} molecules

5 0
3 years ago
How much heat is lost when 0.440 mol of steam condenses at 100 °C?
dusya [7]

Answer:

17,890 J

Explanation:

The amount of heat released by a gaseous substance when it condenses is given by the formula

Q=n\lambda_v

where

n is the number of moles of the substance

\lambda_v is the latent heat of vaporization

The formula can be applied if the substance is at its vaporization temperature.

In this problem, we have:

n = 0.440 mol is the number of moles of steam

\lambda_v=40,660 J/mol is the latent heat of vaporization of water

And the steam is already at 100C, so we can apply the formula:

Q=(0.440)(40660)=17,890 J

8 0
3 years ago
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