Alpha particle is the nuclear decay emission that has the weakest penetrating power. The correct option among all the options that are given in the question is the first option or option "1". Gamma is a type of radiation and so can be negated as a particle. Alpha particles have the largest radiation and so the weakest penetrating power.
Answer:
Helium is created from hydrogen in the sun's core.
Four hydrogen-1 nuclei fuse to produce
- one helium-4 nucleus, two neutrons,
- two positrons, and
- two electron neutrinos.
Explanation:
Step One:
.
Two hydrogen-1 nuclei fuse. One proton will convert to a neutron. The products will be
- one hydrogen-2 nucleus,
- one positron, and
- one electron neutrino.
Step Two:
.
There are plenty of hydrogen-1 nuclei available in the core of the sun. The hydrogen-2 nucleus from step one will fuse with a hydrogen-1 nucleus. The product is
Step Three
.
Two helium-3 nuclei from step two react with each other. The products are:
- one helium-4 nucleus, and
- two hydrogen-1 nuclei.
The overall reaction will be:
.

In other words, hydrogen nuclei in the core of the sun fuse together to form helium.
Answer:
22.67 L of PH₃
Explanation:
The balanced equation is:

From the equation:

= 22.67 L of PH₃
Answer:
319 years
Explanation:
For a radioactive decay we have
N = N₀e^-kt , where:
N= Particles Remainng after a time t
N₀ = Particles Initially present
k = ln 2/ t₁/₂ , t₁/₂ is the half life of the radioactive element (Am-241)
We are given that the half-life is 432 yrs, from this inhformation we can calculate the value of k which then will be used to calculate the time Am-241 will take to decay to 40% once we realize we are given the ratio N/N₀.
k = ln 2/ 432 yr = 0.693/ 432 yr = 1.6 x 10⁻³ /yr
N/N₀ = e^-kt
N/N₀ = 60 (amount remaining after 40 % has decayed)/100
N/N₀ = 0.60
0.60 = e-^-kt
taking natural log to both sides of the equation to get rid of e:
ln (0.60) = -1.6 x 10⁻³ /yr x t ∴ t = - ln (0.60) /1.6 x 10⁻³/ yr
t = 0.51 /1.6 x 10⁻³ yr = 319 yrs
To verify our answer realize that what is being asked is how many years it will take to decay 40 %, and we are told the half life , 50 % decay , is 432 years, so for 40 % we will expect it will take less than that which agrees with our resul of 319 years.