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3 years ago

Assume that temperature and number of moles of gas are constant in this problem.

Chemistry

1 answer:

IrinaVladis [17]3 years ago

4 0

Question:

a. a direct linear relationship

b. an inverse linear relationship

c. a direct nonlinear relationship

d. an inverse nonlinear relationship

Answer:

The correct option is;

d. An inverse nonlinear relationship

Explanation:

From the universal gas equation, we have;

P·V = n·R·T

Where we have the temperature, T and the number of moles, n constant, therefore, we have

P×V = Constant, because, R, the universal gas constant is also constant, hence;

P×V = C

$P = \frac{C}{V}$

Since P varies with V then the graphical relationship will be an inverse nonlinear as we have

V P C

1 5 5

2 2.5 5

3 1.67 5

4 1.25 5

5 1 5

6 0.83 5

7 0.7 5

8 0.63 5

9 0.56 5

10 0.5 5

Where:

V = Volume

P = Pressure

C = Constant = 5

P = C/V

The graph is attached.

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NEED HELP ASAP ITS DUE TODAY THESE QUESTIONS

beks73 [17]

Density can be defined as the mass of the substance in unit volume.

Density = mass / volume

Hence, g/mL and kg/L can be used as the units of density.

Those units are interchangeable because when converting one unit into other one nothing will happen to the value.

That is because when converting the g into kg, you have to multiply the value by 1 x 10⁻³. When converting mL into L, you should again multiply the volume by 1 x 10⁻³. Then those 1 x 10⁻³ will cancel off and the original value will remain as same.

Answer is 2.70 g/mL.

Explanation;

Mass of the block = 146 g

Volume of the block = length x width x height

= 6.0 cm x 3.0 cm x 3.0 cm

= 54 cm³ = 54 mL

Density = mass / volume

= 146 g / 54 mL

= 2.70 g/mL

Answer is 3.39 g/mL.

Explanation;

When immersing an object in a solution, the increased volume indicates the volume of that object.

Hence,

Volume of the object = increased volume of water level

= final volume - initial volume

= 27.8 mL - 21.2 mL

= 6.6 mL

Mass of the object = 22.4 g

Density = Mass / Volume

= 22.4 g / 6.6 mL

= 3.39 g/mL

Accepted value is the value that scientists and community accept as true. This is a theoretical value.

But the measured value is the value that you obtain from doing experiments. This is the actual value.

If your measured value is more close to the accepted value, then your measured value is more precise. But, if your measured value is far away from accepted value means that your value is not precise and there may have some errors.

Answers : Percent error is 9.11 %

The element which has 7.13 g/cm³ as density is Zinc (Zn).

Explanation;

Percent error can be calculated by using following formula.

% error = ( (measured value - accepted value) / accepted value ) x 100%

= ( (7.78 g/cm³ - 7.13 g/cm³) / 7.13 g/cm³ ) x 100%

= 9.11 %

6 0

3 years ago

Calculate the work done when an ideal gas expands isothermally and reversibly in a piston and cylinder assembly for expansion of

pantera1 [17]

Answer:

$W=5743.1077\ J$

Explanation:

The expression for the work done is:

$W=RT \ln \left( \dfrac{P_1}{P_2} \right)$

Where,

W is the amount of work done by the gas

R is Gas constant having value = 8.314 J / K mol

T is the temperature

P₁ is the initial pressure

P₂ is the final pressure

Given that:

T = 300 K

P₁ = 10 bar

P₂ = 1 bar

Applying in the equation as:

$W=8.314\times 300 \ln \left( \dfrac{10}{1} \right)$

$W=300\times \:8.314\ln \left(10\right)$

$W=2.30258\times \:2494.2$

$W=5743.1077\ J$

5 0

3 years ago

why are plasmas of great interest to scientists or manufacturers. descride 2 current uses of plasmas and describe 1 way scientis

Helga [31]

Answer:

Plasmas of great interest to scientists or manufacturers as

Plasma is electrically charged gases that contain considerable charged particles that can change the behavior of the substance.

Current uses of plasmas:

First, it is used to make semiconductors for different types of electronic equipment

Secondly, they're used in making transmitters for high-temperature films.

Way scientists and engineers hope to use plasmas in the future:

The scientists are hoping to use plasma in the future to get rid of all hazardous wastes through a process called plasma gasification.

6 0

3 years ago

24. What volume of a 0.0200M calcium hydroxide is required to neutralize 35.00 mL of 0.0500M nitric acid

Natalka [10]

Answer:

THE VOLUME OF 0.200M CALCIUM HYDROXIDE NEEDED TO NEUTRALIZE 35 mL of 0.050 M NITRIC ACID IS 43.75 mL.

Explanation:

Using

Ca VA / Cb Vb = Na / Nb

Ca = 0.0500 M

Va = 35 mL

Cb = 0.0200 M

Vb = unknown

Na = 2

Nb = 1

Equation for the reaction:

Ca(OH)2 + 2HNO3 --------> Ca(NO3)2 + 2H2O

So therefore, we make Vb the subject of the equation and solve for it

Vb = Ca Va Nb / Cb Na

Vb = 0.0500 * 35 * 1 / 0.0200 * 2

Vb = 1.75 / 0.04

Vb = 43.75 mL

The volume of 0.02M calcium hydroxide required to neutralize 35 mL of 0.05 M nitric acid is 43.75 mL

6 0

3 years ago

While in Europe, if you drive 109 km per day, how much money would you spend on gas in one week if gas costs 1.10 euros per lite

MrRissso [65]

Answer:

The amount is $x = 113.3 \ dollars$

Explanation:

From the question we are told that

The distance traveled per day is $l = 109\ km = \frac{109}{1.609} = 67.74 \ mi$

The cost of one liter is $c = 1.10 \ euros/liter = 1.10 * 1.26 = 1.36 \ dollars/liter$

The car's gas mileage is $b = 22.0 \ mi/gal$

Generally the amount of distance covered in one week is evaluated as

$z = 67.74 * 7$

$z = 474.18 \ mi$

The amount of gas used in one week by the car is mathematically represented as

$k = \frac{ z}{ b}$

=> $k = \frac{ 474.18}{ 22}$

=> $k = 22 \ gal$

converting to liters

$k = 22 * 3.78541=83.28 \ liters$

Thus the amount spent on gas in one week is

$x = k * c$

=> $x = 83.28 * 1.36$

=> $x = 113.3 \ dollars$

5 0

3 years ago