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WARRIOR [948]
3 years ago
6

Explain the energetic benefits of making the enzyme active site complementary to the transition state rather than to the substra

te conformation. Also explain how multiple weak interactions contribute to enzyme action. (In other words, how do these weak interactions between the enzyme and the transition state lower the activation energy?)
Chemistry
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

Explanation:

If the enzyme active site is complementary to the substrate conformation rather than to the transition state, it is unlikely that the reaction will proceed and release a product, because the enzyme-substrate complex will be tightly bound (ΔG will raise).

On the other hand, when the enzyme active site is complementary to the transition state, the substrate will not be tightly bound and will be more prone to be transformed into the product (<u>ΔG will be lowered</u>) and afterward, be released.

The weak interactions (non-covalent bonds) will stabilize the energy of the transition state and reduce its energy, thus lowering the activation energy). If the transition state is stable, it will form more easily and<u> the reaction will be more likely to proceed.</u>

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3 years ago
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3 years ago
The sp of pbbr2 is 6. 60×10−6. what is the molar solubility of pbbr2 in pure water?
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Ksp or Solubility Product Constant is an equilibrium constant for the dissociation in an aqueous solution.

Molar solubility (S) is the concentration of the dissolved substance in a solution that is saturated.

Let the molar solubility be S upon dissociation.

PbBr₂ or Lead Bromide dissociates in pure water as follows:

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Ksp = [Pb⁺²] [ Br⁻]

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6.60 × 10⁻⁶ = 4S³

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Hence, the Molar solubility S is 0.0118M.

Learn more about Molar solubility here, brainly.com/question/16243859

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2 years ago
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I looked on a solubility chart to answer this question, and hydroxides are generally insoluble (with some exceptions of course). However, it says to consider Mg(OH)_{2} as an insoluble substance, though it may be moderately soluble.


The answer that you are most likely looking for is: Yes, a precipitate does form - this is due to the double placement reaction:


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