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WARRIOR [948]
3 years ago
6

Explain the energetic benefits of making the enzyme active site complementary to the transition state rather than to the substra

te conformation. Also explain how multiple weak interactions contribute to enzyme action. (In other words, how do these weak interactions between the enzyme and the transition state lower the activation energy?)
Chemistry
1 answer:
scZoUnD [109]3 years ago
8 0

Answer:

Explanation:

If the enzyme active site is complementary to the substrate conformation rather than to the transition state, it is unlikely that the reaction will proceed and release a product, because the enzyme-substrate complex will be tightly bound (ΔG will raise).

On the other hand, when the enzyme active site is complementary to the transition state, the substrate will not be tightly bound and will be more prone to be transformed into the product (<u>ΔG will be lowered</u>) and afterward, be released.

The weak interactions (non-covalent bonds) will stabilize the energy of the transition state and reduce its energy, thus lowering the activation energy). If the transition state is stable, it will form more easily and<u> the reaction will be more likely to proceed.</u>

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A 13.00 g sample of citric acid reacts with an excess of baking soda What is the theoretical yield of carbon dioxide
viva [34]

Answer:

8.934 g

Step-by-step explanation:

We know we will need a balanced equation with masses and molar masses, so let’s gather all the information in one place.  

M_r:        192.12                                                                   44.01

            H₃C₆H₅O₇ + 3NaHCO₃ ⟶ Na₃C₆H₅O₇ + 3H₂O + 3CO₂

m/g:        13.00

For ease of writing, let's write H₃C₆H₅O₇ as H₃Cit.

(a) Calculate the <em>moles of H₃Cit </em>

n = 13.00 g  × (1 mol H₃Cit /192.12 g H₃Cit)

n = 0.067 67 mol H₃Cit

(b) Calculate the <em>moles of CO₂ </em>

The molar ratio is (3 mol CO₂/1 mol H₃Cit)

n = 0.067 67 mol H₃Cit × (3 mol CO₂/1 mol H₃Cit)

n = 0.2030 mol CO₂

(c) Calculate the <em>mass of CO₂ </em>

m = 0.2030 mol CO₂ × (44.01 g CO₂/1 mol CO₂)

m = 8.934 g CO₂

4 0
3 years ago
15.00 grams of Chromium react with 15.00 grams of hydrobromic acid. Calculate the theoretical yield of the reaction. At STP what
s2008m [1.1K]

Answer:

(a) 18.03 g

(b) 2.105 L

(c) 85.15 %

Step-by-step explanation:

We have the masses of two reactants, so this is a<em> limiting reactant problem.  </em>

We know that we will need a balanced equation with masses, moles, and molar masses of the compounds involved.  

<em>Step 1</em>. <em>Gather all the information</em> in one place with molar masses above the formulas and masses below them.  

M_r:        52.00   80.91       291.71

                2Cr  +  6HBr ⟶ 2CrBr₃ + 3H₂

Mass/g:  15.00    15.00  

<em>Step 2</em>. Calculate the <em>moles of each reactant</em>  

  Moles of Cr = 15.00 × 1/52.00

  Moles of Cr = 0.2885 mol Cr

Moles of HBr = 15.00 × 1/80.91

Moles of HBr = 0.1854 mol HBr ×  

<em>Step 3</em>. Identify the<em> limiting reactant</em>  

Calculate the moles of CrCl₃ we can obtain from each reactant.  

<em>From Cr</em>:

The molar ratio of CrBr₃:Cr is 2 mol CrBr₃:2 mol Cr

Moles of CrBr₃ = 0.2885 × 2/2

Moles of CrBr₃ = 0.2885 mol CrCl₃

<em>From HBr: </em>

The molar ratio of CrBr₃:HBr is 2 mol CrBr₃:6 mol HBr.

Moles of CrBr₃ = 0.1854 × 2/6

Moles of CrBr₃ = 0.061 80 mol CrBr₃

The limiting reactant is HBr because it gives the smaller amount of CrBr₃.

<em>Step 4</em>. Calculate the <em>theoretical yields</em> of CrBr₃ and H₂.

Theoretical yield of CrBr₃ = 0.061 80 × 291.71/1

Theoretical yield of CrBr₃ = 18.03 g CrCl₃

The molar ratio is 3 mol H₂:6 mol HBr

   Theoretical yield of H₂ = 0.1854 × 3/6

   Theoretical yield of H₂ = 0.092 70 mol H₂

<em>Step 5</em>. Calculate the <em>volume of H₂</em> at STP

STP is 1 bar and 0 °C.

The molar volume of a gas at STP is 22.71 L.

Volume = 0.092 70 × 22.71/1

Volume = 2.105 L

<em>Step 6</em>. Calculate the <em>percent yield </em>

       % Yield = actual yield/theoretical yield × 100 %

Actual yield = 15.35 g

       % yield = 15.35/18.03 × 100

       % yield = <em>85.15 % </em>

8 0
3 years ago
How many grams of 2Na + Cl2 would be required to produce 4 grams of table salt?
kondaur [170]
NaCl is table salt so you need 4Na and 4 Cl, So Na₄Cl₄
4 0
3 years ago
I just need help on c-g. The whole question is there in case anyone needs it.
Elza [17]

Answer:

(c) 0.11; (d) -24.5 kJ·mol⁻¹; (e) See below; (f) Kc increases;

(g) No effect on ΔH

Step-by-step explanation:

(c) Kc at 125 °C  

In Part (a) one molecule of XY dissociated into one X and one Y.

       XY ⇌ X + Y

I:      10       0    0

C:     -1       +1   +1

E:      9        1     1

Kc = {[X][Y]}/[XY] = (1 × 1)/9 = ⅑ = 0.11

(d) ΔH

ΔH is a constant that is characteristic of the reaction.

ΔH = -24.5 kJ·mol⁻¹

(e) Effect of temperature on concentrations

If ΔH is negative, the reaction is exothermic.

Heat is a product of the reaction, so we can write the equation as

XY ⇌ X + Y + heat

If we lower the temperature, we are removing heat from the system.

<em>Le Châtelier's Principle</em> states that if you apply a stress to a system at equilibrium, it will respond by trying to relieve the stress.

We applied a stress by removing heat, so the system responds by producing more heat. The position of equilibrium moves to the right, and <em>more products will form</em>.

The diagram might look like the one below.

(f) Effect of temperature on Kc

Kc = [Products]/[Reactants]

We are increasing [Products] and decreasing [Reactants].

If you increase the numerator and decrease the denominator, you i<em>ncrease</em> the value of the quotient.

The value of the equilibrium constant increases when the temperature decreases.

(g) Effect of temperature on ΔH

Decreasing the temperature has no effect on ΔH, because the enthalpies of the reactants and products are properties of the substances themselves. They do not depend on the temperature.

7 0
3 years ago
Without doing any calculations, list the elements in c2h4o2 in order of decreasing mass percent composition.
tia_tia [17]
In <span>c2h4o2 there are
2 atoms of carbon
4 atoms of hydrogen
2 atoms of oxygen

Hydrogen atomic masses is 1 which was very low so 4 of them would still be the lowest mass percent. Then we have carbon and oxygen which both have 2 atoms. Oxygen atomic mass is more than carbon atomic mass, so oxygen should contribute more mass percent composition. The sequence from higher mass percent composition should be:
1. Oxygen
2. Carbon
3. Hydrogen</span>
6 0
3 years ago
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