A disk with a diameter of 0.05 m is spinning with a constant velocity about an axle perpendicular to the disk and running throug

Question

vladimir1956 [14]

3 years ago

5

A disk with a diameter of 0.05 m is spinning with a constant velocity about an axle perpendicular to the disk and running throug

h its center. 1)How many revolutions per second would it have to rotate in order for the acceleration of the outer edge of the disk to be 12 g's (i.e., 12 times the gravitational acceleration g)? f =

Physics

1 answer:

Maksim231197 [3] · Answer 1 · 2022-01-25T05:29:53+03:00

Maksim231197 [3]3 years ago

8 0

Answer:

f= 7.8Hz

Explanation:

a= 12g= 120m/s²

a= ω²r

120= ω²×0.05

ω= 48.99 rad/s

2πf= 48.99

f= 7.8Hz