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vladimir1956 [14]
3 years ago
5

A disk with a diameter of 0.05 m is spinning with a constant velocity about an axle perpendicular to the disk and running throug

h its center. 1)How many revolutions per second would it have to rotate in order for the acceleration of the outer edge of the disk to be 12 g's (i.e., 12 times the gravitational acceleration g)? f =
Physics
1 answer:
Maksim231197 [3]3 years ago
8 0

Answer:

f= 7.8Hz

Explanation:

a= 12g= 120m/s²

a= ω²r

120= ω²×0.05

ω= 48.99 rad/s

2πf= 48.99

f= 7.8Hz

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Answer:

(a) Angular acceleration is 1.112 rad/s².

(b) Average angular velocity is 2.78 rad/s .

Explanation:

The equation of motion in Rotational kinematics is:

θ = θ₀ + 0.5αt²

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α = 1.112 rad/s²

(b) The equation of average angular velocity is:

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A penguin slides at a constant velocity of 1.43 m/s down an icy incline. The incline slopes above the horizontal at an angle of
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Answer:

t =1.285  s

Explanation:

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