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nevsk [136]
3 years ago
6

If two objects have the same mass, what determines the strength of the gravitational force between them? (4 points) Select one:

a. The shape of the objects b. The distance between the objects c. How fast the objects are moving d. How fast the objects are spinning on an axis
Physics
1 answer:
Evgen [1.6K]3 years ago
3 0

According to this equation

F = G × m₁*m₂ ÷ r²

other than the mass, the distance also affects the gravitational force between two objects (same mass or not).

Therefore the correct answer is B. The distance between the objects

Future note* use formulas to help you figure these sort of questions out. (if they have a formula to begin with).

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A 15.0-Ω resistor and a coil are connected in series with a 6.30-V battery with negligible internal resistance and a closed swit
Aloiza [94]

Answer:

0.04328 H

0.00288 seconds

0.01326 seconds

Explanation:

V = Voltage = 6.3 V

R = Resistance = 15 Ω

L = Inductance

I = Decayed current = 0.21 A

t = Time to decay = 2 ms

Maximum Current is given by

I_0=\frac{V}{R}\\\Rightarrow I_0=\frac{6.3}{15}\\\Rightarrow I_0=0.42\ A

Current in the circuit is given by

I=I_0exp\frac{-Rt}{L}\\\Rightarrow ln\frac{I_0}{I}=\frac{Rt}{L}\\\Rightarrow L=\frac{Rt}{ln\frac{I_0}{I}}\\\Rightarrow L=\frac{15\times 2\times 10^{-3}}{ln\frac{0.42}{0.21}}\\\Rightarrow L=0.04328\ H

The inductance is 0.04328 H

Time constant is given by

\tau=\frac{L}{R}\\\Rightarrow \tau=\frac{0.04328}{15}\\\Rightarrow \tau=0.00288\ s

Time constant is 0.00288 seconds

Time required is given by

t=\tau ln\frac{I_0}{I}\\\Rightarrow t=0.00288\times ln\frac{I_0}{0.01I_0}\\\Rightarrow t=0.01326\ s

The time to reach 1% of its original value is 0.01326 seconds

7 0
4 years ago
VI. A student attaches four drawing pins to a copper rod using candle wax as shown in the diagram
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Answer:

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8 0
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olga nikolaevna [1]

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How much time does it take to use 300 W of power to do 1800 J of work? Round your answer to the nearest whole
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6 seconds

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4 0
3 years ago
Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis. Part A What distance should one speaker be placed
Fiesta28 [93]

The distance a speaker should be placed behind  other sound to have an amplitude 1.50 times is 4.523 m.

<h3>What is wavelength?</h3>

The wavelength is the distance between the adjacent crest or trough of the sinusoidal wave. The wavelength is the reciprocal of the frequency of the wave.

Wavelength λ = v/f

Two in-phase loudspeakers emit identical 1000 Hz sound waves along the x-axis.

λ  = 343 m/s /1000 Hz

λ = 0.343 m

Distance, one should speaker be placed behind the other for the sound to have an amplitude 1.50 times that of each speaker alone.

The amplitude of the waveform due to waves,

A = 2a cos (ΔΦ/2)

ΔΦ = 2π x Δx/λ

So, A =  2a cos (π x Δx/λ)

Substitute the values, we get

1.5a = 2a cos (3.14 x  Δx/ 0.343)

Δx = 4.523 m

Thus, the distance is 4.523 m.

Learn more about wavelength.

brainly.com/question/13533093

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7 0
2 years ago
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