Answer:
The ratio of their distance is 9:1
Solution:
As per the question:
Suppose,
Mass of the lighter block = m
Mass of the heavier block, M = 3m
Velocity of the lighter block be v and the velocity of the heavier block be v'.
Now,
The initial momentum of the system is zero.
Therefore,
mv + Mv' = 0
mv = - Mv'
mv = - 3mv'
(1)
Now, if the distance covered by the lighter and the heavier block be d and d' respectively, then by the kinematic eqn:
(2)
(3)
Dividing eqn (2) by (3), we get:
Average speed = (distance covered) / (time to cover the distance)
= (20 miles) / (45 minutes)
Multiply that fraction by (60 minutes / 1 hour) .
This is equal to ' 1 ', so you won't change anything except the units.
= (20 miles / 45 minutes) times (60 minutes / 1 hour)
Multiply the fractions, then cancel 'minutes' out of
the numerator and denominator.
= (20 miles x 60) / (45 x 1 hour)
= (20 x 60 / 45) miles/hour
= 26-2/3 miles/hour .
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<span>Electrons occupy the energy levels of an atom. </span>