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3 years ago

What is noncontact force

Physics

2 answers:

crimeas [40]3 years ago

7 0

Answer:

Non-contact force are forces that exist(arise) without any form of contact between two objects.

Examples are ;

: Magnetic Force ;is a force that attracts certain metal objects (like iron and iron filings) towards a magnet.
Electrostatic Force ;s the force exerted by a charged body on another charged or uncharged body
Gravitational force ; is a force exerted by the earth on all objects on it

Explanation:

Musya8 [376]3 years ago

6 0

Answer:

A non-contact force is a force which acts on an object without coming physically in contact with it.

Explanation:

For example:

Gravitational force.

Magnetic force.

Electrostatics.

Nuclear force.

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Lionel makes a graphic organizer to compare the electric field around a positive charge with the electric field around a negativ

krek1111 [17]

X- points away from the charge
y- points in the direction of the force on the positive charge
z- points toward the charge

6 0

2 years ago

Read 2 more answers

A 2.5 m -long wire carries a current of 8.0 A and is immersed within a uniform magnetic field B⃗ . When this wire lies along the

leva [86]

Answer:

Explanation:

Let the magnetic field be B = B₁i + B₂j + B₃k

Force = I ( L x B ) , I is current , L is length and B is magnetic field .

In the first case

force = - 2.3 j N

L = 2.5 i

puting the values in the equation above

- 2.3 j = 8 [ 2.5 i x ( B₁i + B₂j + B₃k )]

= - 20 B₃ j + 20 B₂ k

comparing LHS and RHS ,

20B₃ = 2.3

B₃ = .115

B₂ = 0

In the second case

L = 2.5 j

Force = I ( L x B )

2.3i−5.6k = 8 ( 2.5 j x (B₁i + B₂j + B₃k )

= - 20 B₁ k + 20B₃ i

2.3i−5.6k = - 20 B₁ k + 20B₃ i

B₃ = .115

B₁ = .28

So magnetic field B = .28 i + .115 B₃

Part A

x component of B = .28 T

Part B

y component of B = 0

Part C

z component of B = .115 T .

8 0

2 years ago

If racing alcohol has a mass density of 790kg/m3, what mass will a 1250-litre tank hold?

Marina86 [1]

Density = Mass per unit Volume
that is,
D = m / V

Now,
We've been provided with,

Density = 790 kg/m³
Volume = 1250 litres = 1.250 m³

Now,
$density = \frac{mass}{volume} \\ 790 = \frac{m}{1.250} \\ 790 \times 1.250 = m \\ m = 790 \times 1.250 \\ m = 790 \times \frac{1250}{1000} \\ m = 790 \times \frac{5}{4} \\ m = 197.5 \times 5 \\ m = \frac{1975}{10} \times 5 \\ m = \frac{1975}{2} = 987.5 \: kg$

987.5 kg of mass will a 1250 litres tank will hold.

Please Mark It As Brainliest Answer_

3 0

3 years ago

Vocabulary word for the total amount of charge in a closed system remains constant

Usimov [2.4K]

Answer:

i think this is it i dont know tho A conservation law stating that the total electric charge of a closed system remains constant over time, regardless of other possible changes within the system. "Conservation of charge." YourDictionary. LoveToKnow

7 0

2 years ago

Two long parallel wires 40 cm apart are carrying currents of 10 A and 20 A in the opposite direction. What is the magnitude of t

Alex_Xolod [135]

Answer:

The magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

Explanation:

Given;

distance half way between the parallel wires, r = ¹/₂ (40 cm) = 20 cm = 0.2 m

current carried in opposite direction, I₁ and I₂ = 10 A and 20 A respectively

The magnitude of the magnetic field halfway between the wires can be calculated as;

$B = \frac{\mu _oI_1}{2 \pi r} + \frac{\mu_oI_2}{2\pi r}$

where;

B is magnitude of the magnetic field halfway between the wires

I₁ is current in the first wire

I₂ is current the second wire

μ₀ is permeability of free space

r is distance half way between the wires

$B = \frac{\mu_o I_1}{2\pi r} + \frac{\mu_o I_2}{2\pi r} \\\\B = \frac{\mu_o }{2\pi r} (I_1 +I_2)\\\\B = \frac{4\pi *10^{-7} }{2\pi *0.2} (10 +20) = 3.0 *10^{-5}\ T$

Therefore, the magnitude of the magnetic field halfway between the wires is 3.0 x 10⁻⁵ T.

5 0

2 years ago