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Anna71 [15]
3 years ago
14

A. If the rock weighs 1050 N, how far does the girl move her end of the lever if the lever is

Physics
1 answer:
3241004551 [841]3 years ago
8 0

student is removing rocks from a garden. She exerts a force of 218 N on a lever to raise one rock a distance of 11.0 cm.

Answer:

52.98 cm

Explanation:

The ratio of forces and distance moved will be the same hence we apply cross multiplication rule

If 218 N can only raise the rock to a distance of 11 cm then we check the distance it can move when force is increased to 1050 N

218 N=11 cm

1050 N=?

By cross multiplication, the distance will be equivalent to \frac {1050\times 11 cm}{218}=52.981651376146\ cm\approx 52.98\ cm

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What is your favorite thing to eat? is it healthy or unhealthy ?
denpristay [2]

Answer:

sometimes I like to eat unhealthy and healthy my healthy are fruits granola a grapes, strawberries, blueberries or make smoothie out  fruits my unhealthy is pizza, streak fries, with everything on the side. so ways  eaanation:

4 0
3 years ago
Bob is moving at 0.967c with respect to Alice. At the exact instant he passes Alice, she fires a very short laser pulse in the s
yulyashka [42]

Explanation:

Speed of Bob, v = 0.967 c

At the exact instant he passes Alice, she fires a very short laser pulse in the same direction Bob is moving.

(a) We need to find the distance measured by Alice  between Bob and the laser pulse. It is given by :

d=ct-vt

d=t(c-v)

d=5.59\times (c-0.967c)

d=5.53\times 10^7\ meters

(b) Distance measured by Bob between himself and the laser pulse is given by :

d_B=ct

d_B=3\times 10^8\times 5.59

d_B=6.67\times 10^9\ meters

Hence, this is the required solution.  

8 0
3 years ago
Help me please this is for physics
Yuri [45]
<h2>Hello there! :)</h2>

It's a pleasure to be helping you today with your<u> physics question!</u>

Answer:

23.1m/s

Explanation:

We want to find the initial speed of the ball.

To do this, we have to apply the formula for the time of flight of a projectile:

T=\frac{2_{v0~sin 0} }{g}

where θ = angle of flight

g = acceleration due to gravity

v0 = initial speed

Therefore, substituting the given values into the formula, we have that:

\boxed{4.2=\frac{2~x~_{v0~sin63} }{9.8}}

⇒ 2 ×_{v0} ×0.8910= 9.8 × 4.2

⇒\boxed{{v0}=\frac{9.8~times~4.2}{2~times~0.8910}}

\boxed{{v0} =23.1m/s}

That is the initial speed of the ball.

<em />

<em>I hope this helps you!</em>

<em>Good Luck with your Assignment!</em>

3 0
2 years ago
22. (I) A car slows down from 28 m/s to rest in a distance of
lidiya [134]

Answer:

a = -8.912 m/s²

Explanation:

Given,

The initial velocity of the car, u = 28 m/s

The final velocity of the car, v = 0

The distance traveled by car, d = 88 m

The velocity displacement relation is given by the formula

                                          v = d/t

∴                                         t = d/v

Substituting in the above values in the given equation

                                           t = 88/28

                                            = 3.142 s

The acceleration is given by the formula

                                         a = (v-u)/t

                                            = (0 - 28)/3.142

                                            = -8.912 m/s²

The negative sign is that the car is decelerating.

Hence, acceleration a = -8.912 m/s²

7 0
3 years ago
For thousands of years people thought that heavier objects fell faster than lighter objects. In fact, this is something that we
Ostrovityanka [42]

Answer:

See below

Explanation:

Gallileo is CORRECT in a vacuum where there is<u> no air friction</u>

  <u>air friction</u> affects same or different weight objects differently  and will cause same-weight   or different weight  objects to fall at different speeds

6 0
2 years ago
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