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Anna71 [15]
3 years ago
14

A. If the rock weighs 1050 N, how far does the girl move her end of the lever if the lever is

Physics
1 answer:
3241004551 [841]3 years ago
8 0

student is removing rocks from a garden. She exerts a force of 218 N on a lever to raise one rock a distance of 11.0 cm.

Answer:

52.98 cm

Explanation:

The ratio of forces and distance moved will be the same hence we apply cross multiplication rule

If 218 N can only raise the rock to a distance of 11 cm then we check the distance it can move when force is increased to 1050 N

218 N=11 cm

1050 N=?

By cross multiplication, the distance will be equivalent to \frac {1050\times 11 cm}{218}=52.981651376146\ cm\approx 52.98\ cm

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Read 2 more answers
Calculate the magnitude of electric field strength at a point 3cm from an infinite line of charge of linear density 18 μC/cm sit
valina [46]
Answer:

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

Explanation:

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\begin{gathered} \lambda=18\mu C\text{ /cm} \\  \\ \lambda=\frac{18*10^{-6}C}{0.01m} \\  \\ \lambda=0.0018\text{ C/m} \end{gathered}

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The electric field strength is calculated below

\begin{gathered} E=\frac{\lambda}{2\pi\epsilon_o\epsilon_rr} \\  \\ E=\frac{0.0018}{2\times3.14\times8.85\times10^{-12}\times1.5\times0.03} \\  \\ E=719709237.468\text{ N/C} \\  \\ E=7.2\times10^8\text{ N/C} \\  \end{gathered}

The magnitude of the electric field strength = 7.2 x 10⁸ N/C

8 0
1 year ago
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