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algol [13]
2 years ago
6

An airline finds that 5% of the persons making reservations on a certain flight will not show up for the flight. If the airline

sells 105 tickets for a flight that has only 100 seats, what is the probability that a seat will be available for every person holding a reservation and planning to fly? (Round your answer to four decimal places.)
Mathematics
1 answer:
Greeley [361]2 years ago
4 0

Answer:

0.5438 = 54.38% probability that a seat will be available for every person holding a reservation and planning to fly

Step-by-step explanation:

We use the binomial approximation to the normal to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

Can be approximated to a normal distribution, using the expected value and the standard deviation.

The expected value of the binomial distribution is:

E(X) = np

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

Normal probability distribution

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

When we are approximating a binomial distribution to a normal one, we have that \mu = E(X), \sigma = \sqrt{V(X)}.

In this problem, we have that:

n = 105, p = 1 - 0.05 = 0.95

I use p = 0.95 because i consider a success a person showing up to the flight. 5% probability that a person misses the flight, so 100-5 = 95% probability that a person shows up to the flight.

For the approximation:

\mu = E(X) = np = 105*0.95 = 99.75

\sigma = \sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{105*0.95*0.05} = 2.23

What is the probability that a seat will be available for every person holding a reservation and planning to fly?

Probability of 100 or less people showing up, which is the pvalue of Z when X = 100. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{100 - 99.75}{2.23}

Z = 0.11

Z = 0.11 has a pvalue of 0.5438

0.5438 = 54.38% probability that a seat will be available for every person holding a reservation and planning to fly

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3 years ago
The sum of the first 10 terms of an arithmetic series is 100 and the sum of next 10 300 .Find the series.​
Free_Kalibri [48]

Let a be the first term in the sequence, and d the common difference between consecutive terms. If aₙ denotes the n-th term in the sequence, then

a₁ = a

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aₙ = a + (n - 1) d

The sum of the first 10 terms is 100, and so

\displaystyle \sum_{n=1}^{10} a_n = 100 \\ \sum_{n=1}^{10} (a + (n-1)d) = 100 \\ (a-d) \sum_{n=1}^{10} 1 + d \sum_{n=1}^{10} n = 100 \\ 10a+45d = 100

where we use the well-known sum formulas,

\displaystyle \sum_{n=1}^N 1 = 1 + 1 + 1 + \cdots + 1 = N

\displaystyle \sum_{n=1}^N n = 1 + 2 + 3 + \cdots + N = \frac{N(N+1)}2

The sum of the next 10 terms is 300, so

\displaystyle \sum_{n=11}^{20} a_n = 300 \\ (a-d) \sum_{n=11}^{20} 1 + d \sum_{n=11}^{20} n = 300 \\ (a-d) \left(\sum_{n=1}^{20} 1 - \sum_{n=1}^{10} 1\right) 1 + d \left(\sum_{n=1}^{20} n - \sum_{n=1}^{10} n\right) = 300 \\ 10a+145d = 300

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d = 2

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10a + 145×2 = 300

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So, the given sequence is simply the sequence of positive odd integers,

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given recursively by the relation

\begin{cases}a_1 = 1 \\ a_n = a_{n-1} + 2 & \text{for }n>1\end{cases}

and explicitly by

a_n = 1 + 2(n-1) = 2n - 1

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1 year ago
Pls help thanks <br> math question
Amiraneli [1.4K]

The solution to the absolute value equation 2|x + 8| - 4 = 16 is x = 2 or x = -18

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more numbers and variables.

An independent variable is a variable that does not depends on other variable while a dependent variable is a variable that depends on other variable.

Given the equation:

2|x + 8| - 4 = 16

2|x + 8| = 20

|x + 8| = 10

x + 8 = 10 or -(x + 8) = 10

x = 2 or x = -18

The solution to the absolute value equation 2|x + 8| - 4 = 16 is x = 2 or x = -18

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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