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3 years ago

There is no air in space astronauts in space cannot hear sounds from outside their spacesuits explain this

Physics

1 answer:

Semmy [17]3 years ago

7 0

<span> In </span>space<span>, where there is no air, sound has no way to travel.</span>

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A parachute increases air friction, thus reducing falling speed.

Indeed, the air friction is roughly proportional to the surface of the object falling down; the parachute tremendously increases that surface.

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3 years ago

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) The square plates of a 5000-pF parallel-plate capacitor measure 50 mm by 50 mm and are separated by a dielectric that is 0.23

notsponge [240]

Answer:

4 x 10⁻⁴ J

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2 years ago

África tiene más de 1000 lenguas, pero solo 50 son habladas por más de 500 mil personas, explica si esto es un aspecto positivo

Misha Larkins [42]

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3 years ago

Dejamos caer un objeto desde lo alto de una torre y medimos el tiempo que tarda en llegar al suelo que resulta ser de 0,02 minut

Harman [31]

Answer: a) 11.76 m/s b) 7.056 m

Explanation:

The described situation is as follows:

An object is dropped from the top of a tower and when measuring the time it takes to reach the ground that turns out to be 0.02 minutes.

This situation is related to free fall, this also means we have constant acceleration, hence the equations we will use are:

$V_{f}=V_{o}+at$ (1)

${V_{f}}^{2}={V_{o}}^{2}+2ad$ (2)

Where:

$V_{f}$ Is the final velocity of the object

$V_{o}=0$ Is the initial velocity of the object (it was dropped)

$a=9.8 m/s^{2}$ is the acceleration due gravity

$d$ is the height of the tower

$t=0.02min=1.2 s$ is the time it takes to the object to reach the ground

b) Begining with (1):

$V_{f}=0+at$ (3)

$V_{f}=at=(9.8 m/s^{2})(1.2 s)$ (4)

$V_{f}=11.76 m/s$ (5) This is the final velocity of the object

a) Substituting (5) in (2):

$(11.76 m/s)^{2}=0+2(9.8 m/s^{2})d$ (6)

Clearing $d$ :

$d=\frac{(11.76 m/s)^{2}}{2(9.8 m/s^{2})}$ (7)

$d=7.056 m$ (8) This is the height of the tower

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3 years ago