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3 years ago

Give the domain and range of each relation. Tell whether the relation is a function. Explain.

Mathematics

2 answers:

Bogdan [553]3 years ago

7 0

The domain is 3 and the range is 2

HACTEHA [7]3 years ago

5 0

What he said. ^^^^^^

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A family went out to eat at a restaurant. Their bill came to $64.20. They want to leave a 20% tip. How much will they leave as a

adelina 88 [10]

Answer:

$12.84

Step-by-step explanation:

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2 years ago

A transformation doubles each point's x-coordinate and leaves the point's y-coordinate intact. What will the transformation have

g100num [7]

It shouldn’t be any longer vertically so that should be your answer

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3 years ago

From a candy machine a random handful of colored chocolate candies are dispensed with 2 quarters. In one turn the machine dispen

Gemiola [76]

Answer:

the answer should be 1/11

Step-by-step explanation:

p(blue first) = 3/12

p(yellow second) = 4/11

so p = 3/12 x 4/11

1/11 is your probability

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2 years ago

Given that P = (-7, 16) and Q = (-8, 7), find the component form and magnitude of vector QP .

Katyanochek1 [597]

Answer:

a)The component form is

$\vec {QP}=\binom{ - 1}{ - 8}$

b)The magnitude is √65

c) <2,14>

Step-by-step explanation:

Recall that:

$\vec {QP}=\vec {OP}-\vec{OQ}$

We substitute the position vectors to get:

$\vec {QP}=\binom{ - 8}{7} - \binom { - 7}{15}$

We subtract the corresponding components to obtain:

$\vec {QP}=\binom{ - 8 - - 7}{7 - 15}$

This gives:

$\vec {QP}=\binom{ - 8 + 7}{7 - 15}$

This simplifies to:

$\vec {QP}=\binom{ - 1}{ - 8}$

The magnitude of a vector in the component form:

$\binom{x}{y}$

$\sqrt{ {x}^{2} + {y}^{2} }$

This means:

$|\vec {QP}|= \sqrt{ {( - 1)}^{2} + {( - 8)}^{2} }$

This simplifies to:

$|\vec {QP}| = \sqrt{ 1 + 64 }$

$|\vec {QP}| = \sqrt{ 65 }$

c) We have the vectors u = <4, 8>, v = <-2, 6>.

We want to find:

u+v

This implies that:

u+v=<4,8>+<-2,6>

We add the corresponding components to get;

u+v=<4+-2,8+6>

This simplifies to:

u+v=<2,14>

7 0

3 years ago

F(x)=x+7<br> if you know the domain is {-9,-3} then the range must be?

RSB [31]

Domain is the set of x-values and range is the set of images f(x).

x           F(x) = x + 7

-9         -9 + 7 = -2

-8         -8 + 7 = -1

-7          -7 + 7 = 0

-6           -6 + 7 = 1

-5           -5 + 7 = 2

-4           -4 + 7 = 3

-3           -3 + 7 = 4

So the range is {-2,4} <------ answer

7 0

3 years ago