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Pavel [41]
4 years ago
13

Suppose you were asked to demonstrate electromagnetic induction. Which of the following situations will result in an electric cu

rrent?
A. A magnet is moving toward a wire loop.
B. A wire loop is moving away from a magnet.
C. A wire loop is rotated near a magnet.
D. All of the above
Physics
2 answers:
steposvetlana [31]4 years ago
5 0
D. All of the above. When a wire loop is moved or rotated in a magnetic field, there is a change in magnetic flux which produces emf in wire loop and hence electric current is produced. 
ad-work [718]4 years ago
3 0
The answer is D. It is obvious since it is a one-choice question and both A and B state the exact same thing. Therefore the answer has to be D and so C has to be correct as well. Exam techniques! :D
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Answer : The velocity of an electron is, 6.1\times 10^{6}m/s

Explanation :

According to de-Broglie, the expression for wavelength is,

\lambda=\frac{h}{p}

and,

p=mv

where,  

p = momentum, m = mass, v = velocity

So, the formula will be:

\lambda=\frac{h}{mv}       .............(1)

where,

h = Planck's constant = 6.626\times 10^{-34}Js

\lambda = wavelength  = 1.2\times 10^{-10}m

m = mass  of electron = 9.11\times 10^{-31}kg

v = velocity of electron = ?

Now put all the given values in formula 1, we get:

1.2\times 10^{-10}m=\frac{6.626\times 10^{-34}Js}{(9.11\times 10^{-31}kg)\times v}

v=6.1\times 10^{6}m/s

Thus, the velocity of an electron is, 6.1\times 10^{6}m/s

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Explanation:

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One complete swing ... to the other side and back to your hand ... does this:
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