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LiRa [457]
3 years ago
5

Macy and Sam are trying to push a large box across a floor. Both girls push with an equal amount of force. The total amount they

exert on the box is 500 Newtons. What amount of force does each girl apply? *
Physics
1 answer:
klemol [59]3 years ago
7 0

Answer:

250 N

Explanation:

Assuming both girls are pushing in the same direction

Given

Total amount of force,they exert on box= 500 N

let <u>force exerted by Macy</u> = F_{M}

     <u>force exerted by Sam</u>= F_{S}

⇒ F_{M}+F_{S}=500 N

But also given <u>both girls push with equal amount of force</u>

⇒ F_{M}=F_{N}

Therefore

F_{M}+ F_{M}=500 N

2\times F_{M}=500 N

F_{M}=250 N

⇒  F_{M}=250 N , F_{N}= 250 N

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A capacitor C is fully charged by connecting it to battery of V Volt. Then it is disconnected from battery. If the separation be
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Answer:

Explanation:

i )

When it is disconnected with the battery , the charge stored in it becomes fixed . When the plate distance becomes half , its capacitance becomes twice from C to 2C . Let charge stored in it at the time of disconnection from battery be Q . Let plate separation reduces from d to d / 2

So charged stored in it will remain unchanged .

ii )

Potential difference = charge / capacitance

in the first case potential difference = Q / C

in the second case potential difference = Q / 2C

So potential difference becomes half .

iii ) electric field = potential diff / plate separation

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in the second case electric field = 2 Q / (d x 2C)

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2 years ago
The electromagnetic wave that delivers a cellular phone callto
spin [16.1K]

Answer:

E=2.41\cdot 10^{-5} J

Explanation:

The intensity of an electromagnetic wave can be expressed in terms of the magnetic field using the next relationship:

I_{average}=\frac{cB_{0}^{2}}{2\mu_{0}} (1)

  • c is the speed of light (3*10⁸ m/s)
  • μ₀ is the permeability of free space (in vacuum ) (1.26*10⁻⁶ N/A²)
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I_{average}=\frac{3\cdot 10^{8}(1.5\cdot 10^{-10})^{2}}{2\cdot 1.26\cdot 10^{-6}}

I_{average}=2.68\cdot 10^{-6} W/m^{2}

Now, let's define the relationship between power (P) and average intensity (I).

I_{average}=\frac{P}{A}

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So we can calculate the power.

P=I_{average}\cdot A=2.68\cdot 10^{-6}\cdot 0.20=5.37\cdot 10^{-7} W

Finally, energy is the product of P times time, so:

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I hope it helps you!

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