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Vera_Pavlovna [14]

2 years ago

5

Wave energy can only be transmitted through a material medium. wave energy can only be transmitted through a material medium.

1 answer:

S_A_V [24]2 years ago

3 0

The correct answer is False.
In fact, electromagnetic waves (which carry energy), do not need a material medium to travel, because they can travel in vacuum as well. So, wave energy can be transmitted also through vacuum.

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A projectile is launched horizontally at a speed of 45.0 m/s from a

Free_Kalibri [48]

Answer:

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2 years ago

Which of these is a push or a pull? Acceleration Force Mass Inertia

Fantom [35]

Answer:

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5 0

2 years ago

The law of conservation of momentum states that the total momentum of interacting objects does not _____. This means the total m

drek231 [11]

Answer:

The law of conservation of momentum states that the total momentum of interacting objects does not <u>change</u>. This means the total momentum <u>before</u><u> </u>a collision or explosion is equal to the total momentum <u>after</u><u> </u>a collision or explosion.

6 0

3 years ago

Read 2 more answers

The distance between the objective and eyepiece lenses in a microscope is 19 cm . The objective lens has a focal length of 5.5 m

kramer

Answer:

The focal length of eyepiece is 3.68 cm.

Explanation:

Given that,

Distance = 19 cm

Focal length = 5.5 mm

Magnification = 200

Object distance = -25 cm

We need to calculate the focal length

Using formula of magnification

$m=\dfrac{d}{f_{o}}+\dfrac{-25}{f_{0}f_{e}}$

Put the value into the formula

$f_{e}=\dfrac{19\times(-25)}{.55(-200-\dfrac{19}{.55})}$

$f_{e}=3.68\ cm$

Hence, The focal length of eyepiece is 3.68 cm.

3 0

3 years ago

A generator uses a coil that has 100 turns and a 0.50-T magnetic field. The frequency of this generator is 60.0 Hz, and its emf

lana [24]

Answer:

38 m

Explanation:

Number of turns=N=100

Magnetic field=B=0.50 T

Frequency of the generator=f=60 Hz

Rms value of emf= $E_{rms}=120 V$

We have to find the length of the wire from which the coil is made.

Peak value of emf= $E_0=E_{rms}\sqrt 2=120\times \sqrt 2=169.7 V$

Length of wire= $4\sqrt{\frac{NE_0}{2\pi fB}}$

Substitute the values

Length of wire= $4\times \sqrt{\frac{169.7\times 100}{0.50\times 2\pi\times 60}}$

Length of wire=38 m

Hence, the length of wire from which the coil is made=38 m

6 0

3 years ago