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Ksivusya [100]
4 years ago
11

The Society of Automotive Engineers has established an accepted numerical scale to measure the viscosity of motor oil. For examp

le, SAE 40 motor oil has a higher viscosity than an SAE 10 oil. Rank the following hydrocarbons by their expected viscosity. Rank from most to least viscous. To rank items as equivalent, overlap them.
a. CH3CH2CH2CH2CH2CH3 b. CH3CH2CH2CH2CH2CH2CH2CH3 c. CH3CH2CH2CH2CH2CH2CH2CH2CH2CH3
Chemistry
1 answer:
natta225 [31]4 years ago
5 0

Answer:

Most viscous to least viscous: (c)> (b)> (a)

Explanation:

For hydrocarbons, viscosity increases with increasing molar mass. Because increasing molar mass signifies increase in number of electrons in molecules.

We know that in non-polar hydrocarbons, only van der waal intermolecular force exists. Van der waal force is proportional to number of electrons in a molecule.

Therefore with increasing molar mass, van der waal force increases. hence molecules gets more tightly bind with each other resulting increase in viscosity.

Here molar mass order : (c)> (b)> (a)

Therefore viscosity order : (c)> (b)> (a)

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How many moles of LiF would be required to produce a 2.5 M solution with a volume of 1.5L
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Multiply the values.

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3 years ago
PLSS HELP ASAP it's due
BartSMP [9]
<h3>Answer:</h3>

87.02%

<h3>Explanation:</h3>

Percent yield of a product in a chemical equation is the ratio of actual or experimental yield to theoretical yield expressed as percentage.

In this case we are given;

Mass of Zinc as 7.23 g

Actual volume of Hydrogen gas produced as 2.16 L

We are required to calculate the percentage yield of Hydrogen gas;

<h3>Step 1: Write a balanced equation for the reaction</h3>

The balanced equation for the reaction between Zinc metal and Hydrochloric acid is given by;

Zn(s) + 2HCl(aq) → ZnCl₂(aq) + H₂(g)

<h3 /><h3>Step 2: Moles of Zinc metal that reacted </h3>

Moles are given by dividing mass with molar mass

Moles = Mass ÷ Molar mass

Molar mass of Zinc = 65.38 g/mol

Therefore;

Number of moles = 7.23 g ÷ 65.38 g/mol

                             = 0.1106 moles

<h3>Step 3: Calculate the number of moles of Hydrogen gas produced</h3>

From the equation 1 mole of Zinc results in the formation of 1 mole of Hydrogen gas.

Therefore, Moles of hydrogen gas = Moles of Zinc × 1

                                                         = 0.1106 moles × 1

                                                         = 0.1106 moles

<h3>Step 4: Calculate the theoretical volume of Hydrogen gas produced.</h3>

At STP, 1 mole of a gas occupies 22.4 Liters

Therefore;

Volume of Hydrogen = Number of moles × 22.4 L

                                   = 0.1106 mole × 22.4 L

                                  = 2.477 L

<h3>Step 5: Calculate the percent yield </h3>

Percent yield = (Actual yield ÷ Theoretical Yield) × 100%

                      = (2.16 L ÷ 2.477 L)× 100%

                     = 87.20%

Thus, the percent yield of hydrogen gas produced is 87.02%

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