Answer:
directly proportional
Explanation:
The Beer-Lambert law states that the quantity of light absorbed by a substance dissolved in a fully transmitting solvent is directly proportional to the concentration of the substance and the path length of the light through the solution.
Answer: <u>Trough </u> can lift the 403,342 ton pioneering spirit crane vessel 10 meters in 30 seconds as if it was a cork. This about 36 GJ if work and 1 GW of power.
Explanation:
Trough is the correct answer because<u> pioneering scale usually abide only on trough not on the other given options</u>. A long , narrow depression between the waves or ridges is known as a trough. The lower point in the period is the trough.
- <u>Speed -:</u> Speed is the distance per unit of time that a body moves. It's a quantity scaler that has just magnitude.
- <u>Wave energy -: </u>The transmission and capture of energy by ocean surface waves is wave energy (or wave power). The energy collected is then used for all sorts of useful work, including the generation of electricity, water desalination, and water pumping.
- <u>Crest -</u>: A crest point within a cycle on a wave with the highest value of upward displacement. A crest is a point on a surface wave where the medium's displacement is at its height.
- <u>Amplitude -:</u> The maximum displacement or distance measured from its equilibrium position, moved by a point on a vibrating body or wave, is called amplitude. It is equal to half of the vibration path's length.
- <u>Period-</u>: The duration T is the time needed to pass a given point for one complete cycle of vibration. The wave length decreases as the frequency of a wave increases.
- <u>Wavelength-:</u> The distance between two successive crests or troughs of a wave can be described as the wavelength. The frequency is inversely proportional to the wavelength. This implies that the longer the wavelength, the smaller the frequency. Similarly, the shorter the wavelength, the higher the frequency would be.
- <u>Frequency</u> -: Frequency defines the number of waves in a given amount of time that travel through a fixed location. In the Hertz unit, frequency is normally measured.
- <u>Information</u> -: A piece of data is a basic fact about the identity or properties of an object, i.e. a portion of its example.
- <u>Milli -</u>: Milli is known as a merged form meaning 'thousand' (millipede) used in the metric system for unit names equal to one thousandth of the base unit (millimeter) given.
Hence , the answer is <u>TROUGH.</u>
Answer:
Explanation:
The question is incomplete.
The equation of motion is given for a particle, where s is in meters and t is in seconds. Find the acceleration after 4.5 seconds.
s= sin2(pi)t
Acceleration = d²S/dt²
dS/dt = 2πcos2πt
d²S/dt² = -4π²sin2πt
A(t) = -4π²sin2πt
Next is to find acceleration after 4.5 seconds
A(4.5) = -4π²sin2π(4.5)
A(4.5) = -4π²sin9π
A(4.5) = -4π²sin1620
A(4.5) = -4π²(0)
A(4.5) = 0m/s²
<em>Answer:</em>
<em>well..</em>
<em>Explana</em><em>tion</em><em>:</em>
<em>L</em><em>iquid</em><em> can flow but solid cannot because of differences in their properties</em>
<em>property of liquid which lets it flow:</em>
- <em>i</em><em>nter-particular</em><em> space is large</em>
- <em>inter-particular attraction is small</em><em> </em><em>t</em><em>hese</em><em> properties tend to make the molecules of liquid free to flow</em><em> </em>
<em>property</em><em> </em><em>of</em><em> </em><em>solid</em><em> </em><em>which</em><em> </em><em>tends</em><em> </em><em>to</em><em> </em><em>obstruct</em><em> </em><em>flow</em><em>:</em>
- <em>inter-particular</em><em> </em><em>spa</em><em>c</em><em>e</em><em> </em><em>is</em><em> </em><em>small</em><em> </em><em>and</em><em> </em><em>so</em><em> </em><em>it's </em><em>compac</em><em>t</em>
- <em>inter-molecular</em><em> </em><em>attra</em><em>ction</em><em> </em><em>is</em><em> </em><em>strong</em><em> </em><em>hence</em><em> </em><em>no</em><em> </em><em>tenden</em><em>cy</em><em> </em><em>to</em><em> </em><em>flow</em>
<em>H</em><em>o</em><em>p</em><em>e</em><em> </em><em>this</em><em> </em><em>helps</em><em>!</em>