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3 years ago

Which point on the roller coaster's path represents the maximum potential energy?

Physics

2 answers:

mariarad [96]3 years ago

8 0

Answer:

Point A (Maximum height)

Explanation:

Potential energy is given as the product of mass, height and acceleration due to gravity hence expressed as mgh where m is the mass of roller coaster, h is the height and g is acceleration due to gravity. Since the mass and g are constant for a roller coaster, the main factor that will influence the magnitude of energy is the height. The higher the height, the higher the potential energy and vice versa. Using the attached image, the highest point is point A

sergeinik [125]3 years ago

8 0

Answer:a

Explanation: Potential energy is defined as mechanical energy, stored energy, or energy caused by its position. The energy that a ball has when perched at a top of a steep hill while it is about to roll down is an example of potential energy which is saying

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A fisherman is fishing from a bridge and is using a "42.0-N test line." In other words, the line will sustain a maximum force of

lara31 [8.8K]

Answer:

(a) 42 N

(b)36.7 N

Explanation:

Nomenclature

F= force test line (N)

W : fish weight (N)

Problem development

(a) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled in at constant speed

We apply Newton's first law of equlibrio because the system moves at constant speed:

∑Fy =0

F-W= 0

42N -W =0

W = 42N

(b) Calculating of weight of the heaviest fish that can be pulled up vertically, when the line is reeled with an acceleration whose magnitude is 1.41 m/s²

We apply Newton's second law because the system moves at constant acceleration:

m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity

∑Fy =m*a

m= W/g , m= W/9.8 , m:fish mass , W: fish weight g:acceleration due to gravity

F-W= ( W/9.8 )*a

42-W= ( W/9.8 )*1.41

42= W+0.1439W

42=1.1439W

W= 42/1.1439

W= 36.7 N

8 0

3 years ago

Help with both questions I’ll mark brainliest

Evgen [1.6K]

Answer:

(1) A sound wave a mechanical wave because mechanical waves rely on particle interaction to transport their energy, they cannot travel through regions of space that are void of particles. Sound is a mechanical wave and cannot travel through a vacuum. These particle-to-particle, mechanical vibrations of sound conductance qualify sound waves as mechanical waves. Sound energy, or energy associated with the vibrations created by a vibrating source, requires a medium to travel, which makes sound energy a mechanical wave. The answer is(B) it travels in the medium.

(2) An ocean wave is an example of a mechanical transverse wave

The compression is the part of the compressional wave where the particles are crowded together. The rarefaction is the part of the compressional wave where the particles are spread apart. The answer is (C) Compression.

3 0

3 years ago

B. Direction: In each of the following situations, identify the method of heat transfer that takes place

Ainat [17]

Answer:

1) Conduction

2)Covection

3)Radiation

4)Convection (Land breeze one of the application of convection of heat)

5) Convection

6)Radiation

7) Radiation

8)Conduction

9) Conduction

10) Radiation

Hope it helps

4 0

3 years ago

A person looking out the window of a stationary train notices that raindrops are falling vertically down at a speed of 3.84 m/s

JulijaS [17]

Answer:

the train is moving at the speed of v = 1.79 m/s

Explanation:

given,

rain drop is falling vertically down with the speed of = 3.84 m/s

angle of the rain drop = 25°

tan θ = $\dfrac{v}{u}$

tan 25° = $\dfrac{v}{3.84}$

v =3.84 × tan 25°

v = 1.79 m/s

hence, the train is moving at the speed of v = 1.79 m/s

3 0

3 years ago

A block of mass m slides on a horizontal frictionless surface. The block is attached to a spring with a spring constant K. At th

Fittoniya [83]

Answer:

b) a = -k / m x , c) d²x / dt² = - A w² cos (wt+Ф) , d) and e) T = 2π √m / k

h) a = - A w² cos (wt+Ф)

Explanation:

a) see free body diagram in the attachment

b) We write Newton's second law

Fe = m a

-k x = ma

a = -k / m x

c) the acceleration is

a = d²x / dt²

If x = A cos wt

v = dx / dt = -A w sin (wt +Ф)

a = d²x / dt² = - A w² cos (wt+Ф)

d) we substitute in Newton's second law

d²x / dt² = -k / m x

We call

w² = k / m

e) substitute to find w

-A w² cos (wt+Ф) = -k / m A cos (wt+Ф)

w² = k / m

Angular velocity and frequency are related

w = 2π f

f = 1 / T

We substitute

T = 2π / w

T = 2π √m / k

g) v= - A w sin (wt+Ф)

h) acceleration is

a = - A w² cos (wt+Ф)

8 0

3 years ago