Given:
1st run: 20 meters North
2nd run: 15 meters East
time: 15 seconds
Average speed = total distance covered / total time taken
Ave. Speed = (20m + 15m) / 15s
Ave. Speed = 35m / 15s
Ave. Speed = 2 1/3 meters per second
It would be option A (a decrease in mass with an increase in volume)
Answer:
51 Ω.
Explanation:
We'll begin by calculating the equivalent resistance of R₁ and R₃. This can be obtained as follow:
Resistor 1 (R₁) = 40 Ω
Resistor 3 (R₃) = 70.8 Ω
Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) =?
Since the two resistors are in parallel connection, their equivalent can be obtained as follow:
R₁ₙ₃ = R₁ × R₃ / R₁ + R₃
R₁ₙ₃ = 40 × 70.8 / 40 + 70.8
R₁ₙ₃ = 2832 / 110.8
R₁ₙ₃ = 25.6 Ω
Finally, we shall determine the equivalent resistance of the group. This can be obtained as follow:
Equivalent Resistance of R₁ and R₃ (R₁ₙ₃) = 25.6 Ω
Resistor 2 (R₂) = 25.4 Ω
Equivalent Resistance (Rₑq) =?
Rₑq = R₁ₙ₃ + R₂ (series connection)
Rₑq = 25.6 + 25.4
Rₑq = 51 Ω
Therefore, the equivalent resistance of the group is 51 Ω.
Explanation:
velocity: average velocity equals Displacement /change in time.
Kinetic energy: K=1/2mv^2 (m = Mass) ( v = Velocity).
speed using the kinetic energy is also KE =1/2mv^2
(M in Kg) (V in m/s)
Answer:
acceleration = 0.022 m/s^2
distance = 8.3 x 10^7 m
speed = 1.9 x 10 ^3 m/s
Explanation:
the parameters given are:
mass = 900kg
force = 20N
- from the formula force = mass x acceleration
acceleration = force / mass
acceleration = 20 / 900
acceleration = 0.022 m/s^2
- distance travelled in 1 day (86,400 seconds) = (1/2) x a x t^2
(1/2) x 0.022 x (86,400^2) = 8.3 x 10^7 m
- speed of the sun yatch (v) = a x t
0.22 x 86400 = 1.9 x 10 ^3 m/s
