Q2 is 1.60x10^-19.
because if you round up or add, you will come with q2
Answer:
(a) 45 micro coulomb
(b) 6 micro Coulomb
Explanation:
C = 3 micro Farad = 3 x 10^-6 Farad
V = 15 V
(a) q = C x V
where, q be the charge.
q = 3 x 10^-6 x 15 = 45 x 10^-6 C = 45 micro coulomb
(b)
V = 2 V, C = 3 micro Farad = 3 x 10^-6 Farad
q = C x V
where, q be the charge.
q = 3 x 10^-6 x 2 = 6 x 10^-6 C = 6 micro coulomb
Answer:
F₃ = -151 N i + 96 N j
Explanation:
Newton's second law:
∑F = m*a Formula (1)
∑F : algebraic sum of the forces in Newton (N)
m : mass s (kg)
a : acceleration (m/s²)
Forces acting on the object
F₁= 3.0 N i + 16.0 N j
F₂ = -12.0 N i+ 8.0 N j
F₃ = F₃x N i +F₃ y N j
x component of the net force on the object
Fx=F₁x+F₂x+F₃ x
Fx = 3.0 N-12.0 N +F₃x
Fx = F₃x - 9 N
y component of the net force on the object
Fy=F₁y+F₂y+F₃ y
Fy =16.0 N+ 8.0 N +F₃y
Fy = F₃y + 24 N
Newton's second law to the object:
a = -8 m/s² i + 6.0 m/s² j
∑Fx = m*ax m=20 kg , ax = -8 m/s²
F₃x - 9 = 20 *(-8)
F₃x = -160+9
F₃x = -151 N
∑Fy = m*ay m=20 kg , ay = 6 m/s²
F₃y + 24 =20*( 6 )
F₃y =120 - 24
F₃y = 96 N
F₃ = -151 N i + 96 N j
If you double the velocity of an object, its momentum doubles. but for the same increase in velocity, the kinetic energy increases 4 times..
1.085m
Explanation:
Using
a= lambda/sinစ
Sinစ= (587.5*10^-9) x 0.75*10^-3
= 0.000783
Sinစ=0.875*10^-3/d
0.000783= 0.875/d
d= 1.085m
