Explanation:
a) 
where
is the distance of the mass
from the axis of rotation. When the axis of rotation is placed at the end of the rod, the moment of inertia is due only to one mass. Therefore,

b) When the axis of rotation is placed on the center of the rod, the moment is due to both masses and the radius r is 1.5 m. Therefore,

T2=r In the form of Kepler's law that can use to relate the period T and radius of the planet in our solar systems
<u>Explanation:</u>
<u>Kepler's third law:</u>
- Kepler's third law states that For all planets, the square of the orbital
period (T) of a planet is proportional to the cube of the average orbital radius (R).
- In simple words T (square) is proportional to the R(cube) T²2 ∝1 R³3
- T2 / R3 = constant = 4π ² /GM
where G = 6.67 x 10-11 N-m2 /kg2
M = mass of the foci body
According to Ohm’s law, the ratio of voltage to current in a conductor is constant.
Answer: Option A
<u>Explanation:</u>
Ohm's law defines that an electric current flowing through the conductor between two ends is directly proportionate to the voltage at these two points. The introduction of a constant proportionality, resistance, gives a simple mathematical equation describing this relationship. Particularly, Ohm's law also mentions that R is constant in this respect, i.e. not dependent on the current.

Where,
I is the current conduction in amperes
V is the voltage calculated by the conductor in volts
R is the conductor’s resistance in ohms.
Answer:
1.35m
Explanation:
At the highest point of the jump, the vertical speed of the skier should be 0. So the 13m/s speed is horizontal, this speed stays the same from the jumping point to the highest point. The 14m/s speed at jumping point is the combination of both vertical and horizontal speeds.
The vertical speed at the jumping point can be computed:




When the skier jumps to the its potential energy is converted to kinetic energy:


where m is the skier mass and h is the vertical distance traveled,
is the vertical velocity at jumping point, and h is the highest point.
Let g = 10m/s2
We can divide both sides of the equation by m:

It takes an average of 8 minutes and 20 seconds.