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mr_godi [17]
1 year ago
11

Antonio has been told that he needs to work on his self- awareness. What might he do to most improve this skill

Physics
1 answer:
m_a_m_a [10]1 year ago
5 0

For Antonio to improve his self-awareness skills he should be able to recognise hie strengths and his weaknesses.

<h3>What is self awareness?</h3>

Self awareness is the act of being able to recognise your feelings and keep your character under control.

To be a self awareness leader, one should be able to have the following qualities:

  • They should be able to recognize their strengths and challenges.
  • They should be able to recognise other people's needs and feelings,
  • They should be able to notice how their behaviour affects the people around them.

Therefore, it can be said for Antonio to improve his self awareness skills, he should be able to recognise his strength and weaknesses and observe how his character affects the people around him.

Learn more about self awareness here:

brainly.com/question/28039248

#SPJ1

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A balloon filled with helium occupies 20.0 l at 1.50 atm and 25.0◦
bija089 [108]
At stp (standard temperature and pressure), the temperature is T=0 C=273 K and the pressure is p=1.00 atm. So we can use the ideal gas law to find the number of moles of helium:
pV=nRT
where p is the pressure (1.00 atm), V the volume (20.0 L), n the number of moles, T the temperature (273 K) and R=0.082 atm L K^{-1} mol^{-1} the gas constant. Using the numbers and re-arranging the formula, we can calculate n:
n= \frac{pV}{RT}= \frac{(1.00atm)(20.0L)}{(0.082 LatmK^{-1}mol^{-1})(273 K)}=0.89 mol
5 0
3 years ago
Consider the two moving boxcars in Example 5. Car 1 has a mass of m1 = 65000 kg and a velocity of v01 = +0.80 m/s. Car 2 has a m
Amiraneli [1.4K]

Answer:

1.034m/s

Explanation:

We define the two moments to develop the problem. The first before the collision will be determined by the center of velocity mass, while the second by the momentum preservation. Our values are given by,

m_1 = 65000kg\\v_1 = 0.8m/s\\m_2 = 92000kg\\v_2 = 1.2m/s

<em>Part A)</em> We apply the center of mass for velocity in this case, the equation is given by,

V_{cm} = \frac{m_1v_1+m_2v_2}{m_1+m_2}

Substituting,

V_{cm} = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

V_{cm} = 1.034m/s

Part B)

For the Part B we need to apply conserving momentum equation, this formula is given by,

m_1v_1+m_2v_2 = (m_1+m_2)v_f

Where here v_f is the velocity after the collision.

v_f = \frac{m_1v_1+m_2v_2}{m_1+m_2}

v_f = \frac{(65000*0.8)+(92000*1.2)}{92000+65000}

v_f = 1.034m/s

8 0
3 years ago
How are animals of the coniferous forest well adapted to long, cold winters?
skelet666 [1.2K]
They have thick body coverings
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3 years ago
How could you use the microscopes from this activity to determine
OlgaM077 [116]

Answer:

The magnification is a function of the lenses in the objective and the eyepiece, so the magnification of the two must be multiplied to obtain the total magnification possible. So, for example, if the objective lens was 4X and the eye piece lens was 10X, the total magnification would be 40. (4 x 10 = 40)

Explanation:

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2 years ago
for an object that is speeding up in the positive direction, what does the displacement vs. time graph look like?
slava [35]

Answer:

The speeding up is steady, it is a parabola (a=V*t+(at^2)/2), and give it's an equation in connection to time, at that point, it is conceivable to discover the separation recipe by utilizing more substantial amount mathematics(integrals).

Explanation:

7 0
3 years ago
Read 2 more answers
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