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3 years ago

8

The _(height or width) of a sound wave determines its _(loudness or pitch).

2 answers:

postnew [5]3 years ago

5 0

<h2>Answer: The <u>height</u> of a sound wave determines its <u>loudness</u> </h2>

Sound waves are longitudinal mechanical waves, that is, they depend on a medium to propagate.

Among the characteristics of a sound wave, it is the amplitude, that is the degree of movement of the molecules of the medium in which the wave propagates.

Depending on how high this amplitude is, the sound will be louder.

Vikki [24]3 years ago

3 0

Answer:

1. height

2. loudness

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Explanation:

Given that,

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de Broglie wavelength = 6.0 nm

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Using formula of energy

$E = \dfrac{hc}{\lambda}$

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(b). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

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$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-9})^2}$

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(c). We need to calculate the energy of photon

Using formula of energy

$E = \dfrac{hc}{\lambda}$

$E=\dfrac{6.63\times10^{-34}\times3\times10^{8}}{6.0\times10^{-15}}$

$E=3.315\times10^{-11}\ J$

(d). We need to calculate the kinetic energy of an electron

Using formula of kinetic energy

$\lambda=\dfrac{h}{\sqrt{2mE}}$

$E=\dfrac{h^2}{2m\lambda^2}$

Put the value into the formula

$E=\dfrac{(6.63\times10^{-34})^2}{2\times9.1\times10^{-31}\times(6.0\times10^{-15})^2}$

$E=6.709\times10^{-9}\ J$

Hence, This is the required solution.

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