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Neko [114]
3 years ago
8

The _____(height or width) of a sound wave determines its _____(loudness or pitch).

Physics
2 answers:
postnew [5]3 years ago
5 0
<h2>Answer: The <u>height</u> of a sound wave determines its <u>loudness</u>  </h2>

Sound waves are longitudinal mechanical waves, that is, they depend on a medium to propagate.

Among the characteristics of a sound wave, it is the amplitude, that is the degree of movement of the molecules of the medium in which the wave propagates.  

Depending on how high this amplitude is, the sound will be louder.

Vikki [24]3 years ago
3 0

Answer:

1. height

2. loudness

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Which of the following benefits has Florida experienced from space exploration? Space exploration has developed better spacesuit
Stolb23 [73]
<span> Space exploration has developed better spacesuits.</span>
5 0
3 years ago
An object is thrown directly downward from the top of a very tall building. The speed of the object just as it is released is 17
Softa [21]

Answer:

distance cover is  = 102.53 m

Explanation:

Given data:

speed of object is 17.1 m/s

t_1 = 3.32 sec

t_2 = 5.08 sec

from equation of motion we know that

d_1 = vt_1 + \frac{1}{2} gt_1^2

where d_1 is distance covered in time t1

sod_1 = 17.1 \times 3.32 + \frac{1}{2} 9.8 \times 3.32^2=

d_1 = 110.78 m

d_2 = vt_2 + \frac{1}{2} gt_2^2

where d_2 is distance covered in time t2

d_2 = 17.1 \times 5.08 + \frac{1}{2}\times9.8 \times 5.08^2

d_2 = 213.31 m

distance cover is  = 213.31 - 110.78 = 102.53 m

3 0
3 years ago
A 100-meter sprint is a race using only the straight side of a racetrack. A 400-meter sprint is a race that makes one complete l
Shalnov [3]
Speed uses distance and velocity uses displacement in its calculation.

For 100 m race, distance = displacement. Hence speed = velocity

For 400m race, distance ≠ displacement. distance = 400m whereas displacement = 0m. Hence speed ≠ velocity
3 0
3 years ago
Read 2 more answers
What is the energy in joules of a mole of photons associated with visible light of wavelength 486 nm?
ivann1987 [24]

Answer:

2.46\cdot 10^5 J

Explanation:

The energy of a single photon is given by:

E=\frac{hc}{\lambda}

where

h is the Planck constant

c is the speed of light

\lambda is the wavelength

For the photon in this problem,

\lambda=486 nm=4.86\cdot 10^{-7}m

So, its energy is

E_1=\frac{(6.63\cdot 10^{-34} Js)(3\cdot 10^8 m/s)}{4.86\cdot 10^{-7}m}=4.09\cdot 10^{-19} J

One mole of photons contains a number of photons equal to Avogadro number:

N_A = 6.022\cdot 10^{23}

So, the total energy of one mole of photons is

E=N_A E_1 = (6.022\cdot 10^{23})(4.09\cdot 10^{-19} J)=2.46\cdot 10^5 J

7 0
4 years ago
A pitcher throws a 0.140 kg baseball, and it approaches the bat at a speed of 35.0 m/s. The bat does Wnc = 75.0 J of work on the
Eva8 [605]

Answer:

The speed of the ball is 42.5 m/s

Explanation:

The initial kinetic energy of the ball is:

K_1=\frac{1}{2} m v_0^2=\frac{1}{2}*0.140 kg*(35.0 m/s)^2= 85.75 J

The speed of the ball after leaving the bat is:

K_2=K_1+W_{nc}\\ \frac{1}{2}mV^2= 85.75 J + 75 J\\ (\frac{1}{2}mV^2)2=( 160.75 J)2\\ mV^2= 321.5 J\\ V^2= \frac{321.5 J}{0.140kg} \\ V=\sqrt{\frac{321.5 J}{0.140kg}}

V=47.92 m/s

Using kinematic equation we can find the speed of the ball after being 25 m above the point of collision:

V_f^2-V^2=-2gh

V_f^2-(47.92 m/s)^2=-2*9.81m/s^2*25m

V_f^2=-2*9.81m/s^2*25m+(47.92 m/s)^2

V_f=\sqrt{-2*9.81m/s^2*25m+(47.92 m/s)^2}

V_f=42.5m/s

3 0
3 years ago
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