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USPshnik [31]
3 years ago
10

A strong man and a weak man are trying to carry a ladder . How should they carry it in such a way that the weak person feels les

s weight of the ladder
Physics
2 answers:
dsp733 years ago
7 0

Answer:

The strong person should carry the ladder at the  front end and the weak person should carry it at the back end.

Explanation:

this is because in such a case the strong person has to pull the ladder whereas the weak person at the back end have to push the ladder. In such case it is easier to push because the weak person can use the force of gravity of his own body for pushing the ladde.

However in case of pulling the ladder one has to overcome his own gravity to pull the heavy object

<u>                                                                                                                                 </u>

<h2><em>I Hope it help you </em></h2>
Natali5045456 [20]3 years ago
7 0

Answer:

  weak person: near the end of the ladder

  strong person: nearer the center of the ladder

Explanation:

The closer the strong person is to the center of mass of the ladder, the greater the fraction of the ladder's weight that person will carry. The weak person will feel less weight if the strong person is nearer to the center of mass.

For example, if the strong person is 3/4 of the ladder's length from the end where the weak person is, then the strong person will carry twice the weight the weak person is having to carry. (Assuming the mass is uniformly distributed.)

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3 years ago
A 13kg box slides 4.0m down the frictionless ramp shown in the figure , then collides with a spring whose spring constant is 170
Svetradugi [14.3K]
The force on the box is:
F = mgsin∅
If we multiply by this with the distance it traveled, we will know the work done by the box. 
W = dmgsin∅

This work will be converted to elastic potential energy in the spring which is:
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7 0
4 years ago
it is required that an object weighing 8N be moved up ward at an acceleration of 2m/s what is the upward force needed ​
sesenic [268]

Answer:

F = 1.6 N

Explanation:

Newton's Second Law of Motion states that whenever an unbalanced force is applied on a body. It produces an acceleration in the body, in its own direction. The magnitude of the force is given by the following formula:

F = ma

where,

F = Force Required to Move the Object Upward = ?

m = mass of object

a = upward acceleration = 2 m/s²

but, we know that weight of object is given as:

Weight = mg

8 N = m(9.8 m/s²)

m = 0.8 kg

using values in the equation:

F = (0.8 kg)(2 m/s²)

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4 0
3 years ago
If the coefficient of static friction at d is μd = 0.3, determine the smallest vertical force that can be applied tangentially t
const2013 [10]

Answer:

The minimum force is required is, f = 0.3 mg  Newton

Explanation:

Given data,

The coefficient of the static friction, μₓ = 0.3

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The minimum force required to set the wheel in motion is equal to the force of static friction. This amount of force can be applied tangentially to the wheel in a vertical direction to set the wheel in motion.

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Where F is the normal force acting on the wheel and it is equal to mg.

Therefore, the minimum force is required is, f = 0.3 mg  Newton

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4 years ago
What does Bohr's model of the atom resemble the most?
erastova [34]
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In short, Your Answer would be Option B

Hope this helps!
6 0
3 years ago
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